Answer:
2% of the progeny will be double crossovers for the trihybrid test cross
Explanation:
By knowing the positions of genes, we can estimate the distances in MU between them per region.
- Genes A and B are 10 map units apart (Region I)
- Genes B and C are 20 map units apart (Region II)
- Genes A and C are 30 map units apart
----A-------10MU--------B-------------20MU-------------C---
Region I Region II
We can estimate the recombination frequencies by dividing each distance by 100.
• recombination frequency of A-B region = 10MU / 100 = 0.10
• recombination frequency of B-C region = 20MU / 100 = 0.20
Now that we know the recombination frequencies in each region, we can calculate the expected double recombinant frequency, EDRF, like this:
EDRF = recombination frequency in region I x recombination frequency in region II.
EDRF = 0.10 x 0.20 = 0.02
2% of the progeny will be double crossovers for the trihybrid test cross
Answer:
The enzyme is Glyceraldehyde-3-phosphate-dehydrogenase. (GAPDH). It is the enzyme that converts Glyceraldehyde-3-phosphate to D-glycerate 1,3-bisphosphate; the sixth Glycolytic pathway for breaking down glucose to ethanol, C02 in Glycolysis. This enzyme requires inorganic phosphate as substrate for the catalytic reaction to proceed. <u>Since enzymatic reactions take place by forming enzyme-substrate complexes</u>, absence of the inorganic phosphate substrate ; stops the conversion and progress of fermentation .
Answer:the condencation is a papas feitas
Explanation:
Answer:
the phyiscal appearance of your genes is called
<h2>
<em><u>PHENOTYPE</u></em></h2>
The answer in here is B. Dalton was incorrect saying that<span> atoms were the indivisible components of matter. Indeed that the atom could not be broken down. </span>
