Answer:
Option 1 and 4 are the two functions.
Step-by-step explanation:
The given graph may be of sine function or cosine function.
So we start with sine function first.
f(x) = asin(bx+c) +d
Here the features of given graph are
1). Amplitude a = (6-0)/2 =3
2). Period = 12 therefore b = 2π/period = 2π/12 = π/6
3). Midline is y = 3
4). Horizontal shift c = 0
5). vertical shift d = 3 in upward direction
5). Since graph starts below the midline means the function will start with negative notation
So we design the function as y = -3sin(π/6+0)+3
Now for cosine function f(x) = a cos(bx+c)+d
1). Amplitude a = 3
2). Midline is y = 3
3). period = 2π therefore b = 2π/period = 2π/12 = π/6
4). Horizontal shift which is in right side, c = +(π/2)
5). Vertical shift d = 3
Therefore the cosine function will be f(x) = 3cos(π/6+π/2)+3