Answer:
The estimated probability that Ginger will eat a a pizza everyday of the week is;
D. 8/10 = 80%
Step-by-step explanation:
The given parameters are;
The frequency with which Ginger buys launch = Everyday
The percentage of the time the cafeteria has pizza out = 80%
The outcome of 0 and 1 = No pizza available
The outcome of 2, 3, 4, 5, 6, 7, 8, and 9 = Pizza available
Therefore, we have the;
Group number
Percentage of time pizza available
1
80%
2
80%
3
80%
4
80%
5
40%
6
100%
7
80%
8
100%
9
80%
10
80%
Therefore, the sum of the percentages outcome the days Ginger eats pizza = 0.8 + 0.8 + 0.8 + 0.8 + 0.4 + 1 + 0.8 + 1 + 0.8 + 0.8 = 8
The number of runs of simulation = 10 runs
The estimated probability that Ginger will eat a a pizza everyday of the week = (The sum of the percentages outcome the days Ginger eats pizza)/(The number of runs of simulation)
∴ The estimated probability that Ginger will eat a a pizza everyday of the week = 8/10
Answer:
It would be B
Step-by-step explanation:
Answer:
$62.50 because
Step-by-step explanation:
250÷4=62r2
62.50•4=250
Answer:
Its C
Step-by-step explanation:
All you have to do is divide 90.2 by 11
First of all, find the first number more than 100 that can divided by 9, and it's 108 (we'll call it as 'a') then, find the number less than 2000 that can divided by 9, it's 1.998 (we'll call it as 'Un')
Un = a + (n-1).b
1998 = 108 + (n-1).9
1998 = 108 + 9n -9
1899 = 9n
211 = n
and the total is
Sn = n/2 (a+un)
s211 = 211/2 (108+1998)
= 222.183