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3 years ago

Need answers as soon as possible, will give brainiest and rate 5/5.

2 answers:

8 0

1)45
2)5
3)20
4)x-9=17
5) 2x+3=35
6)0
7)-2/9(THIS IS NOT IN THE CHOICES BUT IT IS THE RIGHT ANSWER).
8)x-(-2)
9)Subtract 7 and then divide by -2
10)-16
11)5x=11
12)Division property
13)-27
14)20
15)2x-5=15
16)-16
17)168
18)-5

aliya0001 [1]3 years ago

3 0

1. x/-3=-15
x=45

2. -7+3(-12)÷-3
-7+12
5

3. f(-4)=(-4)²-(-4)
f(-4)=16-(-4)
f(-4)=20

4. x-9=17

5. 2x+3=35

6. -8-12-(-20)
-20-(-20)
0

7. -2(-3)²(-1)
-2(9)(-1)
-18(-1)
18

8. x-(-2)

9. subtract 7 then divide by -2

10. 6+(-18)+(-13)+9
-12-4
-16

11. 5x=11

12. division property

13. -3³ = -27

14. x/2-3=7
x/2=10
x=20

15. 2x-5=15

16. x/-4-(-8)=12
x/-4=4
x=-16

17. 168

18. 16-20-(-8)-9
-4-(-8)-9
4-9
-5

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A 12 foot board is cut so that one piece is 5 times as long as the other. Find the length of each piece.

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Answer:

2 and 10

Step-by-step explanation:

Let x be length of the small piece and y the length of the big one.

● y = 5x

Since the big piece is 5 times longer than the short one.

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3 years ago

Suppose that the distribution of typing speed in words per minute (wpm) for experienced typists using a new type of split keyboa

KengaRu [80]

Answer:

a. 0.5 or 50%

b. 0.496 or 49.6%

c. 0.8185 or 81.85%

d. Yes, it would be just 0.0013 or 0.13% of probability to find a typist whose speed exceeds 105 wpm

e. 0.0252 or 2.52%

f. The qualifying speed would be 47.4 wpm.

Step-by-step explanation:

a. Let's find the z-score this way:

μ = 60 σ= 15

z-score = (x - μ)/σ

z-score = (60 - 60)/15

z-score = 0

Now, let's calculate the p value for z-score = 0, using the z-table:

p (z=0) = 0.5 or 50%

b. z-score = (x - μ)/σ

z-score = (59.9 - 60)/15

z-score = -0.01

Now, let's calculate the p value for z-score = -.0.01, using the z-table:

p (z = -0.01) = 0.496 or 49.6%

If the question were less or equal than 60, a and b would have the same answer. But in this case, the question is "less than 60 wpm".

z-score = (x - μ)/σ

z-score = (45 - 60)/15

z-score = - 1

Now, let's calculate the p value for z-score = -1, using the z-table:

p (z = -1) = 0.1587

z-score = (x - μ)/σ

z-score = (90 - 60)/15

z-score = 2

Now, let's calculate the p value for z-score = 2, using the z-table:

p (z = 2) = 0.9772

In consequence,

p (-1 ≤ z ≤ 2) = 0.9772 - 0.1587 = 0.8185 or 81.85%

d. z-score = (x - μ)/σ

z-score = (105 - 60)/15

z-score = 3

Now, let's calculate the p value for z-score = 3, using the z-table:

p (z = 3) = 0.9987

In consequence,

p (z > 3) = 1 - 0.9987 = 0.0013

Yes, it would be just a 0.13% of probability to find a typist whose speed exceeds 105 wpm.

e. z-score = (x - μ)/σ

z-score = (75 - 60)/15

z-score = 1

Now, let's calculate the p value for z-score = 1, using the z-table:

p (z = 1) = 0.8413

In consequence,

p (z > 1) = 1 - 0.8413 = 0.1587

and if the two typists are independently selected, then

p = 0.1587 * 0.1587

p = 0.0252 or 2.52%

f. p = 0.2, using the z-table, the z-score is -0.84, then:

z-score = (x - μ)/σ

-0.84 = (x - 60)/15

-12.6 = x - 60

-x = -60 + 12.6

-x = - 47.4

x = 47.4

The qualifying speed would be 47.4 wpm.

8 0

3 years ago

An iceberg weights 450,000 pounds. If it loses 0.2% of its weight in a day, what is its new weight at the end of the day?

Papessa [141]

Answer:

449,100 pounds

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