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aliya0001 [1]
3 years ago
9

You have 10 batteries sitting on your desk, three of which are dead. You choose 2 batteries are random for you calculator. What

is the expected number of good batteries that you get?
A) 0

B) 1

C) 1.4

D) 2
Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
7 0

Answer:

C) 1.4

Step-by-step explanation:

The probability of choosing 2 good ones is 7/10·6/9 = 42/90.

The probability of choosing 1 good one is 7/10·3/9 +3/10·7/9 = 42/90.

The probability of choosing 0 good ones is 3/10·2/9 = 6/90

The expected value is the sum of the product of number of good ones and their probability:

... 2·42/90 +1·42/90 +0·6/90 = (2+1)·42/90 = 42/30 = 1.4

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There are 135 skiers in line to ride the chair lift. If each chair seats 7 people, how many skiers will be on the last chair?
Hatshy [7]

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19

Step-by-step explanation:

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2 years ago
2. (x3 – 6x2) (x – 7)
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Answer:

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Step-by-step explanation:

5 0
3 years ago
If the average yield of cucumber acre is 800 kg, with a variance 1600 kg, and that the amount of the cucumber follows the normal
lorasvet [3.4K]

Answer:

a

   The  percentage is

            P(x_1 <  X <  x_2 ) =   51.1 \%

b

   The probability is  P(Z >  2.5 ) =  0.0062097

Step-by-step explanation:

From the question we are told that

        The  population mean is  \mu =  800

        The  variance is  var(x) =  1600 \ kg

        The  range consider is  x_1 =  778 \ kg  \  x_2 =  834 \ kg

         The  value consider in second question is  x =  900 \ kg

Generally the standard deviation is mathematically represented as

        \sigma =  \sqrt{var (x)}

substituting value

        \sigma =  \sqrt{1600}

       \sigma = 40

The percentage of a cucumber give the crop amount between 778 and 834 kg  is mathematically represented as

       P(x_1 <  X <  x_2 ) =  P( \frac{x_1 -  \mu }{\sigma} <  \frac{X - \mu }{ \sigma } < \frac{x_2 - \mu }{\sigma }   )

    Generally  \frac{X - \mu }{ \sigma } = Z (standardized \  value  \  of  \  X)

So

      P(x_1 <  X <  x_2 ) =  P( \frac{778 -  800 }{40} < Z< \frac{834 - 800 }{40 }   )

      P(x_1 <  X <  x_2 ) =  P(z_2 < 0.85) -  P(z_1 <  -0.55)

From the z-table  the value for  P(z_1 <  0.85) =  0.80234

                                            and P(z_1 <  -0.55) =   0.29116  

So

             P(x_1 <  X <  x_2 ) =   0.80234 - 0.29116

             P(x_1 <  X <  x_2 ) =   0.51118

The  percentage is

            P(x_1 <  X <  x_2 ) =   51.1 \%

The probability of cucumber give the crop exceed 900 kg is mathematically represented as

             P(X > x ) =  P(\frac{X - \mu }{\sigma }  > \frac{x - \mu }{\sigma } )

substituting values

             P(X > x ) =  P( \frac{X - \mu }{\sigma }  >\frac{900 - 800 }{40 }   )

             P(X > x ) =  P(Z >2.5   )

From the z-table  the value for  P(Z >  2.5 ) =  0.0062097

 

7 0
3 years ago
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