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egoroff_w [7]
3 years ago
10

Solve the problem. Round the solution to the nearest hundredth where applicable. What is the tangent of ZH?

Mathematics
1 answer:
kumpel [21]3 years ago
6 0
B because tangent is Opposite/hypotenuse. = 6/8 = 0.75
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Kirsten has to walk 2 3/4km to school. How far has she walked when she halfway? Give your answer in metres.
evablogger [386]

Answer:

375 m

Step-by-step explanation:

\frac{3}{4}  \times 1000 = 750

From halfway

\frac{750}{2}  = 375

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3 years ago
The sum of two numbers is 22. the difference is 6 what are the two numbers?
Nataly [62]

Answer:

8,14

Step-by-step explanation:

Let one number = x

Other number = 22-x

x - (22-x) = 6

x - 22 +x =6

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x = 14

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8 0
3 years ago
The difference between rational and irrational
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Answer:

Every integer is a rational number, since each integer n can be written in the form n/1. For example 5 = 5/1 and thus 5 is a rational number. However, numbers like 1/2, 45454737/2424242, and -3/7 are also rational, since they are fractions whose numerator and denominator are integers.

Step-by-step explanation:

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3 0
3 years ago
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What is the length of the side of a right triangle that has a side length of 20 mm and a hypotenuse of 25 mm?
Marta_Voda [28]
I don't know but I think it is C
6 0
3 years ago
1) After a dilation, (-60, 15) is the image of (-12, 3). What are the coordinates of the image of (-2,-7) after the same dilatio
BARSIC [14]

Answer:

a) k = 5; (-10, -35)

Step-by-step explanation:

Given:

Co-ordinates:

Pre-Image = (-12,3)

After dilation

Image = (-60,15)

The dilation about the origin can be given as :

Pre-Image(x,y)\rightarrow Image(kx,ky)

where k represents the scalar factor.

We can find value of k for the given co-ordinates by finding the ratio of x or y co-ordinates of the image and pre-image.

k=\frac{Image}{Pre-Image}

For the given co-ordinates.

Pre-Image = (-12,3)

Image = (-60,15)

The value of k=\frac{-60}{-12}=5

or k=\frac{15}{3}=5

As we get k=5 for both ratios i.e of x and  y co-ordinates, so we can say the image has been dilated by a factor of 5 about the origin.

To find the image of (-2,-7), after same dilation, we will multiply the co-ordinates with the scalar factor.

Pre-Image(-2,-7)\rightarrow Image((-2\times5),(-7\times 5))

Pre-Image(-2,-7)\rightarrow Image(-10,-35) (Answer)

7 0
3 years ago
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