First, make up some variables to represent the number of Girls and Boys in the choir.
B = number of boys
G = number of girls
You know that there are 4 times as many girls in the choir as boys. Therefore, the equation you can write is:
If you cross-multiply, then you get the simplified equation:
G = 4B
Intuitively this makes sense since if you multiplied the number of boys in the class by 4, that would be equal to the number of girls you have.
Now, we know that the total class size is 60. So girls plus boys equals 60:
G+B = 60
To solve the equation, replace the G in this equation with the replacement you found before, 4B.
G + B = 60 -->
4B + B = 60 -->
5B = 60 -->
B = 12
However, you are trying to find the number of girls, so plug the answer back into your equation.
G + B = 60 -->
G + 12 = 60 -->
G + 12 -12 = 60 - 12 -->
G = 48
The number of girls you have is 48.
Answer:
D. 9/DF=18/16.......the answer
The best, closest quotient would be 87.
<h3>Therefore, correct option is C. option.</h3><h3>C. x=29/8c</h3>
Answer:
The measure of angle LMN is 68° ⇒ the last answer
Step-by-step explanation:
* Lets revise the properties of the rhombus
- The rhombus has 4 equal sides in length
- Every two opposite angles are equal in measure
- Every two adjacent angles are supplementary (their sum = 180°)
- The two diagonals bisect each other
- The two diagonals perpendicular to each other
- The two diagonals bisect the vertices angles
* Lets solve the problem
∵ LMNO is a rhombus
∴ ∠LMN and ∠MNO are adjacent angles
∴ ∠LMN and ∠MNO are supplementary
∴ m∠LMN + ∠MNO = 180°
∵ m∠MNO = 112°
∴ m∠LMN + 112° = 180° ⇒ subtract 112 from both sides
∴ m∠LMN = 68°
* The measure of angle LMN is 68°