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tatiyna
3 years ago
15

mr. Garcias class raised momey for a field trip to the zoo. There are 23 students in his class. The cost of the trip will be $17

for each student.What is the cost fir all the students?
Mathematics
2 answers:
Paul [167]3 years ago
6 0

Answer:

They both determined that  

✔ 35

people are going.

Which property illustrates that they should have gotten the same answer?  

✔ commutative property

Step-by-step explanation:

Mandarinka [93]3 years ago
4 0

Answer:

The cost for all of the students is $391

Step-by-step explanation:

Since it costs $17 for each student and there are 23 students, you multiply 17 and 23 to get the cost for all students.

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Step-by-step explanation:

This is a subtraction problem.

45 - 40 = 5

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netineya [11]

Answer:

The first question is (n*8) - 4

The second question is no.

Step-by-step explanation:

The first question, you add 8. The first is 1. 1 * 8 = 8 - 4 = 4.

Therefore, the equation is (n*8) - 4

The second question, you can plug in numbers. You can solve for a term.  -100 + 17 = -83. -83 is not a multiple of -4. -100 is not a term.

8 0
3 years ago
Suppose that a college determines the following distribution for X = number of courses taken by a full-time student this semeste
lidiya [134]

Answer:

E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74In order to find the variance we need to calculate first the second moment given by:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36And the variance is given by:

Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924

And the deviation would be:

Sd(X) =\sqrt{0.8924} =0.9447

Step-by-step explanation:

Previous concepts

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).  

Solution to the problem

For this case we have the following distribution given:

X          3      4       5        6

P(X)   0.07  0.4  0.25  0.28

We can calculate the mean with the following formula:

E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74

In order to find the variance we need to calculate first the second moment given by:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36

And the variance is given by:

Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924

And the deviation would be:

Sd(X) =\sqrt{0.8924} =0.9447

3 0
3 years ago
Please help me out!!!!!!!!!!!!
Lesechka [4]

9514 1404 393

Answer:

  see below

Step-by-step explanation:

A number line usually has numbers increasing from the right. If each unit on the number line represents $100, then a gain of $500 would be represented by the point at +5 units (right of 0). The loss would be represented by a point at -5 units, located left of 0.

The points are equidistant from 0 in opposite directions.

3 0
3 years ago
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