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Lilit [14]
3 years ago
15

Twice a number plus twice a second number is 310. The difference between the numbers is 55

Mathematics
1 answer:
agasfer [191]3 years ago
4 0

Answer:

x = 105

y = 50

Step-by-step explanation:

To solve this, try writing it out as an equation/expression first.

When you do, you should get something like this:

2x + 2y = 310

x - y = 55

This is a system of equations. To solve this, we're going to multiply the second equation [x - y = 55] by 2.

2(x - y = 55) = 2x - 2y = 110

Now, subtract your new equation from the first one [2x + 2y = 310]

2x + 2y = 310

-2x + 2y = -110

//<em>If you</em>'<em>re wondering why I changed the signs of the new equation, I multiplied our new equation [2x - 2y = 110] by -1 since we're subtracting//</em>

When you're done subtracting, the "2x" and "-2x" cancel out, so you're left with:

4y = 200

Now, simply solve for "y" by dividing both sides by 4.

4y = 200

y = 50

Now that we know y's value, substitute it into one of our original equations to solve for x.

//<em>I'm gonna plug y into the second equation [x - y = 55] just because it's easier, but you can plug it into the first one as well and get the same answer//</em>

When we plug it in, we get:

x - (50) = 55

To solve for "x," we must get rid of "-50." To do this, add 50 to both sides.

x - 50 = 55

x = 105

<u>So, x = 105 and y = 50</u>

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four families go to the cinema. the reid family take 2 adults and 2 children for £18 ; the mghee family take 1 senior, 2 adults
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Answer:

\pounds 26.50

Step-by-step explanation:

Let

x = cost for one adult

y = cost for one child

z = cost for one senior.

<u>The Reid family:</u>

take 2 adults and 2 children and paid 2x+2y that is \pounds 18, so

2x+2y=18

<u>The Mghee family:</u>

take 1 senior, 2 adults and 1 child and paid x+2x+y that is \pounds 18.50, so

x+2x+y=18.50

<u>The Griffiths family:</u>

take 1 senior and 3 adults and paid z+3x that is \pounds 19.50, so

z+3x=19.50

You get the system of three equations:

\left\{\begin{array}{l}2x+2y=18\\ \\z+2x+y=18.50\\ \\z+3x=19.50\end{array}\right.

From the first equation:

2y=18-2x\\ \\y=9-x

From the third equation:

z=19.50-3x

Substitute them into the second equation:

19.50-3x+2x+9-x=18.50\\ \\-3x+2x-x=18.50-19.50-9\\ \\-2x=-10\\ \\2x=10\\ \\x=5

Then

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Hence,

the cost for one adult is \pounds 5

the cost for one child is \pounds 4

the cost for one senior is \pounds 4.50

<u>The Linton family</u> takes 1 senior, 2 adults and 3 children and paid

\pounds 4.50+2\cdot \pounds 5+3\cdot \pounds 4=\pounds 26.50

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hope this helps! :)</span>
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