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yanalaym [24]
3 years ago
7

How do you do these problems

Mathematics
1 answer:
Elden [556K]3 years ago
8 0

Well for the first one, that is presumably a straight line and straight lines all have 180 degrees. So you add 61 and 23 to get 84 and subtract that from 180. You then get 96 degree.

For the second one corresponding angles on a transversal are congruent so x+95=4x-10 and then you solve the equation.;

For the third one you need to make the change from 9 to 12 be the same as the change from 3 to t. 9 to 12 is 4/3 so 3 times 4/3 is 4. t=4

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d

Step-by-step explanation:

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Alecsey [184]

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stiv31 [10]

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Step-by-step explanation:

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djyliett [7]

this is the answer to this question - Two weather tracking stations are on the equator 146 miles apart. A weather balloon is located on a bearing of N 35°E from the western station and on a bearing of N 23°E from the eastern station. How far is the balloon from the western station?

Answer:

Reasons:

The given parameters are;

Distance between the two stations = 146 miles

Location of the weather balloon from the Western station = N35°E

Location of the weather balloon from the Eastern station = N23°E

The location of the station = On the equator

Required:

The distance of the balloon from the Western station

Solution:

- The angle formed between the horizontal, and the line from the Western station

to the balloon = 90° - 35° = 55°

- The angle formed between the horizontal, and the line from the Eastern station

to the balloon = 90° + 23° = 113°

The angle at the vertex of the triangle formed by the balloon and the two stations is 180° - (55 + 113)° = 12°

By sine rule,

Distance from balloon to western station = 146/sin(12 dg) = Distance from balloon to western station/sin(113 dg)

Therefore;

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Step-by-step explanation:

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Answer:

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