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TEA [102]
3 years ago
9

You are in the pit crew for a driver at a Nascar race. The gas weighs 5.92 pounds

Mathematics
1 answer:
jenyasd209 [6]3 years ago
4 0

Answer:

plz give the ques properly

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almond37 [142]
Answer: B. Exponential. There is a constant rate of decay or decrease. 

The y-values decrease by 1/4 of the number that comes before every time. 
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Solve for x<br><br> 15x^2+16x= -4
Klio2033 [76]
15x²+16x+4 =0      (ax² +bx +c=0)

Δ = b²-4ac =256 - 4×15×4 =16

x1 = (-b+√Δ) / 2a = (-16+√16) / 30 =( -16+4) / 30 = -12/30 = - 2/5
x2 = (-b -√Δ) / 2a = (-16 -√16) / 30 = (-16 -4) /30 = -20/30 = -2/3
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3 years ago
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Tape diagram make an equation 6t 9
natta225 [31]

Answer:

The answer would be 0.6666666666666666666666666666666666666666667

Step-by-step explanation:

6/9 equals 0.66666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666667

6 0
3 years ago
What is a number between 7.833 and 7.834
dalvyx [7]

7.8335 is a number between 7.833 and 8.834

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3 years ago
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Twelve percent of U.S. residents are in their forties. Consider a group of nine U.S. residents selected at random. Find the prob
miskamm [114]

Answer:

The probability is 28 % ( approx )

Step-by-step explanation:

Since, there are only two possible outcomes in every trails ( residents are in their forties or not ),

So, this is a binomial distribution,

Binomial distribution formula,

Probability of success in x trials,

P(x)=^nC_x p^x q^{n-x}

Where, ^nC_x=\frac{n!}{x!(n-x)!}

p and q are probability of success and failure respectively and n is the total number of trials.

Let X be the event of resident who are in his or her forties.

Here, p = 12% = 0.12,

⇒ q = 1 - p = 1 - 0.12 = 0.88,

n = 9,

Hence, the probability that two or three of the people in the group are in their forties = P(X=2) + P(X=3)

^9C_2 (0.12)^2 (0.88)^{9-2}+^9C_3 (0.12)^3 (0.88)^{9-3}

=36(0.12)^2 (0.88)^7+84(0.12)^3 (0.88)^6

=0.279266611163

\approx 0.28

=28\%

7 0
3 years ago
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