Answer:
Spreadsheet values
- B3 = $15 (shown)
- C4 = $420 (shown)
- D6 = $272.5
- E4 = $6
- F2 = $16
- F6 = $5
Other values
- profit maximizing Q: 35
- profit maximizing P: $13
- maximum profit: $227.5
Step-by-step explanation:
Labeling the columns of the spreadsheet A--F, and the rows 1--7, we want to find the values as follows.
a) The relationship between quantity, price, and revenue is ...
total revenue = quantity × price
price = (total revenue)/quantity
Then ...
- B3 = 375/25 = 15 (as shown)
- C4 = 30×14 = 420 (as shown)
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b) The relationship between total cost and marginal cost is ...
mc2 = (tc2 -tc1)/(q2 -q1)
tc2 = (mc2)(q2 -q1) +tc1
Then ...
- D6 = 9(40 -35) +227.5 = 272.5
- E4 = (192.5 -162.5)/(30 -25) = 6
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c) Marginal revenue is figured the same way as marginal cost.
mr2 = (r2 -r1)/(q2 -q1)
Then ...
- F2 = (320 -0)/(20 -0) = 16
- F6 = (480 -455)/(40 -35) = 5
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d) The quantity maximizing profit will be the quantity such that marginal revenue is equal to marginal cost. That is, marginal profit is zero. That quantity is 35, where both marginal cost and marginal revenue are 7.
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e) The price at a quantity of 35 is 13. This value is read from the given table.
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f) The maximum profit is the difference between revenue and cost at the profit-maximizing quantity:
maximum profit = 455 -227.5 = 227.5
For which set of data is the mode 3? A 6, 2, 7, 6, 6, 6, 3, 1, 3, 9, 3 B 3, 12, 8, 5, 1, 4, 11, 13, 11, 2 C 5, 7, 3, 8, 4, 3, 5,
gizmo_the_mogwai [7]
Answer:
Step-by-step explanation:
The mode in statistics is the number that occurs the most in a data set.
So you basically have to find the set that has the most threes.
A and C both have 3 threes. I think there might be another 3 in one of those if there has to be only one answer.
So the answer can be either A or C.
Hope this helps!
X^2 + Y^2 = 4 This centers at origin, since h and k values are zero ( therefore nonexistent) and the radius is 2 so it goes through (-2,0)
Answer:
B, C, and D
Step-by-step explanation:
They all have lower values than 2.1
Would a bake sale flyer work?