Answer:
B. the trials must be dependent
Step-by-step explanation:
The image for the question is attached.
The missing options are;
A. The probability of a success remains the same in all trials.
B. The trials must be dependent.
C. Each trial must have all outcomes classified into two categories.
D. The procedure has a fixed number of trials.
For a binomial distribution probability, the event must be repeated for a number of time (n) and the probability of success (q) must be the same during each trial.
Binomial distribution probability has two possible outcome: success (p) or failure (q). The event are also independent of each other.
The formula for a binomial distribution probability is given as:
P(X=x) = nCx (p ^ x) (q ^ (n-x))
From the above, we can see that the answer is:
B. the trials must be dependent
The slope of the first equation is -2, you can see it right off.
the slope of the second equation is 2, notice both are in slope-intercept form.
both equations are the equations of a line, so is really just two lines.
because their slope differs, they're not parallel or equivalent, therefore, they lines do meet at some point, and one point only, and therefore, they have 1 solution only.
a system of equations with at least 1 solution, is a consistent system.
a consistent system with exactly 1 solution only, is not just consistent, but also independent.
Let x be her initial distance from the building, then tan 37 = 130/x
x = 130/tan 37 = 130/0.7536 = 172.5 feet
Let y be her distance from the building after moving forward, then
tan 40 = 130/y
y = 130/tan 40 = 130/0.8391 = 154.9
After moving forward, she is 172.5 - 154.9 = 17.6 ft closer.
Answer:
this image is unreadable please take a clearer picture.
Step-by-step explanation:
Answer:
Step-by-step explanation:
1. False D' is in quad 4
2. True it is reflected about the y axis. That puts it in 3. If it was rotated about the x axis, it would be in quad 1
3. As long as there is no point going through the origin, then the statement in 3 is true. You have to understand that in quad 4 all y values are minus.
4. False. If D was entirely contained in quad 2, then in quad 3 the x values will be minus. As a matter of fact, so will the y values.
