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emmasim [6.3K]
3 years ago
10

you want to put 520 quarters in coin wrappers. you need one wrapper for every $10 in quarters. write an equation you can use to

find how many wrappers you need
Mathematics
1 answer:
Lisa [10]3 years ago
6 0
40c=520
This is the proper equation because there are 40 quarters in $10. Thus, if we could only fit $10 worth of quarters in each wrapper, we can only fit 40quarters in each wrapper. C represents the amount of wrappers we will need.

Hope this helps!
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Answer: (a). at x = 0, its a removable discontinuity

and at x = 1, it is a jump discontinuity

(b). at x = -3, it is removable discontinuity

also at x = -2, it is an infinite discontinuity

(c). at x = 2, it is a jump discontinuity

Step-by-step explanation:

in this question, we would analyze the 3 options to determine which points gave us discontinuous in the category of discontinuity as jump, removable, infinite, etc.

(a). given that f(x) = x/x² -x

this shows a discontinuous function, because we can see that the denominator equals zero i.e.

x² - x = 0

x(x-1) = 0

where x = 0 or x = 1.

since x = 0 and x = 1, f(x) is a discontinuous function.

let us analyze the function once more we have that

f(x) = x/x²-x = x/x(x-1) = 1/x-1

from 1/x-1 we have that x = 1 which shows a Jump discontinuity

also x = 0, this also shows a removable discontinuity.

(b). we have that f(x) = x+3 / x² +5x + 6

we simplify as

f(x) = x + 3 / (x + 3)(x + 2)

where x = -3, and x = -2 shows it is discontinuous.

from f(x) = x + 3 / (x + 3)(x + 2) = 1/x+2

x = -3 is a removable discontinuity

also x = -2 is an infinite  discontinuity

(c). given that f(x) = │x -2│/ x - 2

from basic knowledge in modulus of a function,

│x│= │x       x ˃ 0 and at │-x    x ∠ 0

therefore, │x - 2│= at │x - 2,     x ˃ 0 and at  │-(x - 2)   x ∠ 2

so the function f(x) = at│ 1,     x ˃ 2 and at │-1,    x ∠ 2

∴ at x = 2 , the we have a Jump discontinuity.

NB. the figure uploaded below is a diagrammatic sketch of each of the function in the question.

cheers i hope this helps.

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