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pashok25 [27]
2 years ago
11

What is the solution to this equation? -1/5(x+1 1/4)=-2 1/2

Mathematics
2 answers:
lubasha [3.4K]2 years ago
8 0

\large\displaystyle\text{$\begin{gathered}\sf -\frac{1}{5}\left(x+1\frac{3}{4}\right)=-2\frac{1}{2}    \end{gathered}$}

Multiply both sides of the equation by 20, the lowest common denominator of 5,4,2.

\large\displaystyle\text{$\begin{gathered}\sf \bf{-4\left(x+\frac{4+3}{4}\right)=-10(2\times2+1)  } \end{gathered}$}

Add 4 and 3 to get 7.

\large\displaystyle\text{$\begin{gathered}\sf \bf{-4\left(x+\frac{7}{4}\right)=-10(2\times2+1)  } \end{gathered}$}

Use the distributive property to multiply −4 times x 4/7.

\large\displaystyle\text{$\begin{gathered}\sf \bf{-4x-4\times\left(\frac{7}{4}\right)=-10(2\times2+1)  } \end{gathered}$}

Multiply −4 by 4/7.

\large\displaystyle\text{$\begin{gathered}\sf \bf{-4x-7=10(2\times2+1) \ \ \to \ \ [Multiply \ 2\times2] }  \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf \bf{-4x-7=10(4+1) \ \ \to \ \ [Add] }  \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf \bf{-4x-7=10\times5 \ \ \to \ \ [Multiply] }  \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf \bf{-4x-7=-50 } \end{gathered}$}

Add 7 to both sides.

\large\displaystyle\text{$\begin{gathered}\sf \bf{-4x=-50+7 \ \ \to \ \ [Add] } \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf \bf{-4x=-43 } \end{gathered}$}

Divide both sides by −4.

\large\displaystyle\text{$\begin{gathered}\sf \bf{x=\frac{-43}{-4} } \end{gathered}$}

The fraction \bf{\frac{-43}{-4}} can be simplified to \bf{\frac{43}{4}} by removing the negative sign from the numerator and denominator.

\large\displaystyle\text{$\begin{gathered}\sf \bf{x=\frac{43}{4} } \end{gathered}$}

simplify

\large\displaystyle\text{$\begin{gathered}\sf \bf{x=10\frac{3}{4} \ \ \to \ \ \ Answer } \end{gathered}$}

<h2>{ Pisces04 }</h2>
Tomtit [17]2 years ago
5 0

Answer:

\sf c)\ x=10\dfrac{3}{4}

Step-by-step explanation:

<u>Given equation:</u>

\sf -\dfrac{1}{5}\left(x+1\dfrac{3}{4}\right)=-2\dfrac{1}{2}

<u>Step 1:</u> Convert the mixed numbers into improper fractions.

\sf -\dfrac{1}{5}\left(x+\dfrac{4\times1+3}{4}\right)=-\dfrac{2\times2+1}{2}\implies -\dfrac{1}{5}\left(x+\dfrac{7}{4}\right)=-\dfrac{5}{2}

<u>Step 2:</u> Distribute -⅕ through the parentheses.

\sf-\dfrac{1}{5}(x)+-\dfrac{1}{5}\left(\dfrac{7}{4}\right)=-\dfrac{5}{2}\\\\\implies -\dfrac{1}{5}x-\dfrac{7}{20}=-\dfrac{5}{2}

<u>Step 3:</u> Rewrite the equation with a common denominator of 20.

\sf -\dfrac{1\times4}{5\times4}x-\dfrac{7}{20}=-\dfrac{5\times10}{2\times10}\\\\\implies -\dfrac{4}{20}x-\dfrac{7}{20}=-\dfrac{50}{20}

<u>Step 4:</u> Multiply both sides by 20.

\sf 20\left(-\dfrac{4}{20}x\right)-20\left(\dfrac{7}{20}\right)=20\left(-\dfrac{50}{20}\right)\\\\\implies -4x-7=-50

<u>Step 5:</u> Add 7 to both sides.

\sf -4x-7+7=-50+7\\\\\implies -4x=-43

<u>Step 6:</u> Divide both sides by -4.

\sf \dfrac{-4x}{-4}=\dfrac{-43}{-4}\\\\\implies x=\dfrac{43}{4}


<u>Step 7:</u> Convert the answer back into a mixed number.

\sf x=\dfrac{43}{4}\implies x=\dfrac{40+3}{4}\implies x=10\dfrac{3}{4}

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