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pashok25 [27]
2 years ago
11

What is the solution to this equation? -1/5(x+1 1/4)=-2 1/2

Mathematics
2 answers:
lubasha [3.4K]2 years ago
8 0

\large\displaystyle\text{$\begin{gathered}\sf -\frac{1}{5}\left(x+1\frac{3}{4}\right)=-2\frac{1}{2}    \end{gathered}$}

Multiply both sides of the equation by 20, the lowest common denominator of 5,4,2.

\large\displaystyle\text{$\begin{gathered}\sf \bf{-4\left(x+\frac{4+3}{4}\right)=-10(2\times2+1)  } \end{gathered}$}

Add 4 and 3 to get 7.

\large\displaystyle\text{$\begin{gathered}\sf \bf{-4\left(x+\frac{7}{4}\right)=-10(2\times2+1)  } \end{gathered}$}

Use the distributive property to multiply −4 times x 4/7.

\large\displaystyle\text{$\begin{gathered}\sf \bf{-4x-4\times\left(\frac{7}{4}\right)=-10(2\times2+1)  } \end{gathered}$}

Multiply −4 by 4/7.

\large\displaystyle\text{$\begin{gathered}\sf \bf{-4x-7=10(2\times2+1) \ \ \to \ \ [Multiply \ 2\times2] }  \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf \bf{-4x-7=10(4+1) \ \ \to \ \ [Add] }  \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf \bf{-4x-7=10\times5 \ \ \to \ \ [Multiply] }  \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf \bf{-4x-7=-50 } \end{gathered}$}

Add 7 to both sides.

\large\displaystyle\text{$\begin{gathered}\sf \bf{-4x=-50+7 \ \ \to \ \ [Add] } \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf \bf{-4x=-43 } \end{gathered}$}

Divide both sides by −4.

\large\displaystyle\text{$\begin{gathered}\sf \bf{x=\frac{-43}{-4} } \end{gathered}$}

The fraction \bf{\frac{-43}{-4}} can be simplified to \bf{\frac{43}{4}} by removing the negative sign from the numerator and denominator.

\large\displaystyle\text{$\begin{gathered}\sf \bf{x=\frac{43}{4} } \end{gathered}$}

simplify

\large\displaystyle\text{$\begin{gathered}\sf \bf{x=10\frac{3}{4} \ \ \to \ \ \ Answer } \end{gathered}$}

<h2>{ Pisces04 }</h2>
Tomtit [17]2 years ago
5 0

Answer:

\sf c)\ x=10\dfrac{3}{4}

Step-by-step explanation:

<u>Given equation:</u>

\sf -\dfrac{1}{5}\left(x+1\dfrac{3}{4}\right)=-2\dfrac{1}{2}

<u>Step 1:</u> Convert the mixed numbers into improper fractions.

\sf -\dfrac{1}{5}\left(x+\dfrac{4\times1+3}{4}\right)=-\dfrac{2\times2+1}{2}\implies -\dfrac{1}{5}\left(x+\dfrac{7}{4}\right)=-\dfrac{5}{2}

<u>Step 2:</u> Distribute -⅕ through the parentheses.

\sf-\dfrac{1}{5}(x)+-\dfrac{1}{5}\left(\dfrac{7}{4}\right)=-\dfrac{5}{2}\\\\\implies -\dfrac{1}{5}x-\dfrac{7}{20}=-\dfrac{5}{2}

<u>Step 3:</u> Rewrite the equation with a common denominator of 20.

\sf -\dfrac{1\times4}{5\times4}x-\dfrac{7}{20}=-\dfrac{5\times10}{2\times10}\\\\\implies -\dfrac{4}{20}x-\dfrac{7}{20}=-\dfrac{50}{20}

<u>Step 4:</u> Multiply both sides by 20.

\sf 20\left(-\dfrac{4}{20}x\right)-20\left(\dfrac{7}{20}\right)=20\left(-\dfrac{50}{20}\right)\\\\\implies -4x-7=-50

<u>Step 5:</u> Add 7 to both sides.

\sf -4x-7+7=-50+7\\\\\implies -4x=-43

<u>Step 6:</u> Divide both sides by -4.

\sf \dfrac{-4x}{-4}=\dfrac{-43}{-4}\\\\\implies x=\dfrac{43}{4}


<u>Step 7:</u> Convert the answer back into a mixed number.

\sf x=\dfrac{43}{4}\implies x=\dfrac{40+3}{4}\implies x=10\dfrac{3}{4}

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andrey2020 [161]

Adding and subtracting big polynomials like these are pretty easy. You just need to combine like terms. For example:

1.)

{5x}^{2}  +  {3x}^{2}  =  {8x}^{2}

2.)

({3x}^{2}  + 5xy) + (7xy + 2) =

{3x}^{2} + 12xy + 2

(The 3x^2 and the 2 stay intact while the 5xy and 7xy combine together)

All you have to do is combine the numbers that have the same powers of x and y with each other. x^2 will combine with x^2 and xy^2 wil combine with xy^2 exc. If there is no other number with the same x and y's, then you just leave it as it is in the answer.

Now with the original question, I see a -9xy^3, and thats gonna combine with the 3xy^3 in the second polynomial and the 2xy^3 in the third one.

- 9x {y}^{3}  + 3x {y}^{3}  + 2x {y}^{3} = \\  - 4x {y}^{3}

So far we have -4xy^3, the next term is going to be a -9x^4y^3, and that's gonna combine with the 3x^4y^3 in the third one.

- 9 {x}^{4} {y}^{3}  + 3 {x}^{4}  {y}^{3}  =  - 6{x}^{4}  {y}^{3}

We now finished adding the like terms that were in the first polynomial, we will move onto the second polynomial. The first term in this one is 3xy^3, in which we already added in the first step. At this point, it doesn't look like there are any other terms that have the same x and y behind them. So we can move on and write the final answer:

- 4x {y}^{3} - 6 {x}^{4} {y}^{3}  + 7 {y}^{4}  \\ - 8 {x}^{4} {y}^{4}

(All on the same line of course)

Also, for your second question, the order does not matter in which you write the terms. I could write the 7y^4 behind the -8x^4y^4 and it would still be the same answer.

If you have any other questions let me know :) while I double check my work.

6 0
4 years ago
The diagram below represents the measurements of Jennie’s yard. The yard’s width is x feet shorter than its length. If the area
professor190 [17]

Answer: The width is 12 feet shorter than the length.

Step-by-step explanation:

The area of a rectangle can be calculated with this formula:

A=lw

Where "l" is the lenght and "w" is the width of the rectangle.

 We know that lenght of Jennie's yard is 30 feet, the width is (30-x)ft and the area is 540 square feet. Then:

l=30\\w=(30-x)\\A=540

Substitute these values into the formula and then solve for "x":

A=lw\\\\540=30(30-x)\\\\540=900-30x\\\\30x=900-540\\\\x=\frac{360}{30}\\\\x=12

Therefore, the width is 12 feet shorter than the length.

4 0
4 years ago
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balandron [24]
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3 0
4 years ago
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Please help! Worth 25 points :)
Daniel [21]

Answer:

b

Step-by-step explanation:

5(0)-3(-4)=12 that simply's to 0+12=12

its no subtraction sign cause cant have a double negative

7 0
3 years ago
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