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d1i1m1o1n [39]
3 years ago
8

-1(x+5)=3[x+(2x-1)] solved and justified each step

Mathematics
1 answer:
madreJ [45]3 years ago
6 0

Answer:

<h2>x = -0.2</h2>

Step-by-step explanation:

-1(x+5)=3[x+2x-1)]\\\\\text{for}\ -1(x+5):\ \text{distribtutive property}\\\text{for}\ [x+(2x-1)]:\ \text{associative property}\\\\(-1)(x)+(-1)(5)=3[(x+2x)-1]\\-x-5=3(3x-1)\\\\\text{for}\ 3(3x-1):\ \text{distributive property}\\\\-x-5=(3)(3x)+(3)(-1)\\-x-5=9x-3\\\\\text{for the equation}:\ \text{addition property of equality}\\\\-x-5=9x-3\qquad\text{add 5 to both sides}\\-x-5+5=9x-3+5\\-x=9x+2\\\\\text{for the equation:}\ \text{subtraction property of equality}\\\\-x=9x+2\qquad\text{subtract}\ 9x\ \text{from both sides}

-x-9x=9x-9x+2\\-10x=2\\\\\text{for the equation:}\ \text{division property of equality}\\\\-10x=2\qquad\text{divide both sides by -10}\\\dfrac{-10x}{-10}=\dfrac{2}{-10}\\x=-0.2

\text{Distributive property:}\ a(b+c)=ab+ac\\\text{Associative property:}\ (a+b)+c=a+(b+c)

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Which ordered pairs are in the solution set of the system of linear inequalities? y &gt; x y &lt; x + 1 (5, –2), (3, 1), (–4, 2)
steposvetlana [31]

To check which ordered pair (point) is in the solution set of the system of given linear inequalities y>x, y<x+1; we just need to plug given points into both inequalities and check if that point satisfies both inequalities or not. If any point satisfies both inequalities then that point will be in solution.

I will show you calculation for (5,-2)

plug into y>x

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which is clearly false.

plug into y<x+1

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or -2<6

which is also false.

hence (5,-2) is not in the solution.

Same way if you test all the given points then you will find that none of the given points are satisfying both inequalities.

Hence answer will be "No Solution from given choices".

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</span></span></span></span>
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