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11Alexandr11 [23.1K]
3 years ago
9

Each week samantha can pay as much as $15 for her school lunch. Write an inequality showing how much samantha spends on lunch.

Mathematics
1 answer:
Annette [7]3 years ago
5 0

Answer:

x\leq \$15

Step-by-step explanation:

Let

x------> amount of money that Samantha spends weekly on her school lunch

we know that

The inequality that represent this situation is

x\leq \$15

All positive real number less than or equal to 15

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Answer:

The slope is 1/2

Step-by-step explanation:

To find the slope

m= (y2-y1)/(x2-x1)

   = (8-2)/(5--7)

   = (8-2)/(5+7)

    = 6/12

     = 1/2

5 0
4 years ago
What is the result of 5 divided by one-fifth? 5 fraction bars. Each bar is labeled 1 with 5 boxes labeled one-fifth underneath.
FromTheMoon [43]

Answer:

25

Step-by-step explanation:

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3 years ago
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I don’t understand how to do any of this. can someone please help me?
kolezko [41]

Answer:

first use the Pythagoras theorem to find for a,b and c

that is. c²= b²+a²

then when you find the answers find the area of A,B and C

that is <u>1</u>× base × height

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8 0
3 years ago
Eighteen telephones have just been received at an authorized service center. Six of these telephones are cellular, six are cordl
LenaWriter [7]

Answer:

a) 0.0498

b) 0.1489

c) 0.1818

Step-by-step explanation:

Given:

Number of telephones = 6+6+6= 18

6 cellular, 6 cordless, and 6 corded.

a) Probability that all the cordless phones are among the first twelve to be serviced:

12 are selected from 18 telephones, possible number of ways of selection = ¹⁸C₁₂

Then 6 cordless telephones are serviced, the remaining telephones are: 12 - 6 = 6.

The possible ways of selecting thr remaining 6 telephones = ¹²C₆

Probability of servicing all cordless phones among the first twelve:

= (⁶C₆) (⁶C₁₂) / (¹⁸C₁₂)

= \frac{1 * 924}{18564}

= 0.0498

b) Probability that after servicing twelve of these phones, phones of only two of the three types remain to be serviced:

Here,

One type must be serviced first

The 6 remaining to be serviced can be a combination of the remaining two types.

Since there a 3 ways to select one type to be serviced, the probability will be:

= 3 [(⁶C₁)(⁶C₅) + (⁶C₂)(⁶C₄) + (⁶C₃)(⁶C₃) + (⁶C₄)(⁶C₂) + (⁶C₅)(⁶C₁)] / ¹⁸C₁₂

= \frac{3 * [(6)(6) + (15)(15) + (20)(20) + (15)(15) + (6)(6)]}{18564}

= \frac{2766}{18564}

= 0.1489

c) probability that two phones of each type are among the first six:

(⁶C₂)³/¹⁸C₆

\frac{3375}{18564}

=0.1818

5 0
4 years ago
Question 3
Galina-37 [17]

(a) The vertical motion equation for the ball is h = 8 + 48t - 16t².

(b) The time for the ball to hit the ground is 3.15 s.

(c) The time for the ball to travel 56 ft above the ground is 0.79 s.

<h3>Vertical motion equation for the ball</h3>

The vertical motion equation for the ball is calculated as follows;

h = h₀ + vt - ¹/₂gt²

h = 8 + 48t - ¹/₂(32)t²

h = 8 + 48t - 16t²

<h3>Time for the ball to hit the ground</h3>

0 = 8 + 48t - 16t²

solve the above quadratic equation with formula method;

a = -16, b = 48, c = 8

t = 3.15 s

<h3>Time for the ball to be 56 ft above the ground</h3>
  • let upward motion be positive

h = 8 + 48t + 16t²

56 = 8 + 48t + 16t²

0 = -48 + 48t + 16t²

solve the above quadratic equation with formula method;

a = 16, b = 48, c = -48

t = 0.79 s

Learn more about equation of motion here: brainly.com/question/25951773

#SPJ1

5 0
3 years ago
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