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stepan [7]
3 years ago
14

Is y=3x + 3 or y=5x - 6 steeper?

Mathematics
1 answer:
babymother [125]3 years ago
7 0
Y=5x-6 is steeper
 thatsur annwser
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3 (x - 4) = 5 + 3x + 2
alexdok [17]
3x-12= 3x + 7
+12 +12
3x = 3x + 19
-3x -3x
x = 19

8 0
3 years ago
12 out of 30 tickets sold were early admission what percentage of tickets were early admission tickets
bezimeni [28]

Answer:

40%

Step-by-step explanation:

12 divided by 30 will give you 0.4

7 0
3 years ago
PLEASE HELP ME!!! WHOEVER CAN!!
Alex787 [66]

Answer:

deltamath right? lol understand

Step-by-step explanation:

since there are 5 questions im gonna have to explain it to u.

for this one you need numbers that are greater than or equal to -6. So

06, -5.999999 -5.99 -5.9 -5 -3 -1 and 2 :)

7 0
3 years ago
HELLO ANY MATH EXPERTS HERE THEN PLEASE ANSWER THIS !!!
Iteru [2.4K]

-6x-2y = -18\\\\\text{Plug y = 0}\\\\-6x  = -18 \implies x = \dfrac{-18}{-6} = 3\\\\\text{Hence the coordinates of the x-intercept are given by (3,0)}

8 0
3 years ago
Read 2 more answers
Prove the statement holds for all positive integers:<br><br> 2 + 4 + 6 + ... + 2n = n² + n
crimeas [40]

Proving a relation for all natural numbers involves proving it for n = 1 and showing that it holds for n + 1 if it is assumed that it is true for any n.

The relation 2+4+6+...+2n = n^2+n has to be proved.

If n = 1, the right hand side is equal to 2*1 = 2 and the left hand side is equal to 1^1 + 1 = 1 + 1 = 2

Assume that the relation holds for any value of n.

2 + 4 + 6 + ... + 2n + 2(n+1) = n^2 + n + 2(n + 1)

= n^2 + n + 2n + 2

= n^2 + 2n + 1 + n + 1

= (n + 1)^2 + (n + 1)

This shows that the given relation is true for n = 1 and if it is assumed to be true for n it is also true for n + 1.

<span>By mathematical induction the relation is true for any value of n.</span>

6 0
3 years ago
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