All categories

3 years ago

This graph represents which of these expressions?

Mathematics

1 answer:

Lelu [443]3 years ago

6 0

Answer:

x > 43

Step-by-step explanation:

Open circle at 43, which means it is not equal to 43

Line goes to the right, which means x is greater than

x > 43

You might be interested in

Someone plz help me T^T

IRINA_888 [86]

Answer:24 red 48 yellow and 24 white.

Step-by-step explanation:

Math

8 0

3 years ago

Consider a 25 factorial design. (a) How many factors and levels are considered in this factorial experiment

Bad White [126]

Answer:

Step-by-step explanation:

From the information given;

We are to take a look at a 2⁵ factorial design.

The factorial design consists of carrying out the design of equipment by testing it by modifying not the parameters one by one but by modifying several simultaneous parameters.

An experiment is termed to be a 2⁵ factorial experiment if in the experiment 5 factors are studied consecutively with each at two-level.

Thus, there are five factors and 2 levels in the experiment.

8 0

3 years ago

Write the equation of a line that is parallel to y=6x+1 and that passes through (-7, 1)

Orlov [11]

Answer: y = 4x + 43

Step-by-step explanation: In the photo

4 0

3 years ago

Read 2 more answers

RAY CUPPLE BOUGHT A BASIC CAR COSTING $26,500.00 WITH OPTIONS COSTING $725.00 THERE IS A 6% SALES TAX IN HIS STATE AND A COMBINE

Virty [35]

<span>$28, 908.50 is the answer</span>

4 0

4 years ago

The height of a trapezoid is 8 in. And its area is 96 in2. One base of the trapezoid is 6 inches longer than the other base. Wha

Vsevolod [243]

Answer:

The lengths of the bases are 9 inches and 15 inches.

Step-by-step explanation:

The area of trapezoid is

$=\frac12(\textrm{ sum of parallel sides})\times height$

Given that the height of a trapezoid is 8 in. and its area is 96 in².

Assume the bases of the trapezoid be b₁ and b₂.

Since one base of the trapezoid 6 in. longer than the other.

Let, b₁=b₂+6

The area of the trapezoid is

$=\frac 12 (b_1+b_2)\times8$ in²

$=\frac12 (b_2+6+b_2)\times 8$ in²

$=\frac12(2b_2+6)\times8$ in²

According to the problem,

$\frac12(2b_2+6)\times8 =96$

$\Rightarrow 2b_2+6=\frac{96\times 2}{8}$ [ Multiplying $\frac28$ ]

$\Rightarrow 2b_2+6=24$

$\Rightarrow 2b_2=24-6$

$\Rightarrow 2b_2=18$

$\Rightarrow b_2=\frac{18}{2}$

$\Rightarrow b_2=9$

Then, $b_1=b_2+6$

=9+6

=15 in

The lengths of the bases are 9 inches and 15 inches.

5 0

3 years ago