Ask question

Ask question

All categories

antoniya [11.8K]

2 years ago

6

Holly has 56 peices of paper and 8 paper clips. If she clips the same amount of paper together with each paper clip, how many pe

ices will be clipped together with each paper clip?

1 answer:

dedylja [7]2 years ago

3 0

Answer:

56/8 = 7 pieces of paper

Step-by-step explanation:

You might be interested in

I need to find the least common denominator of x+2/x^2+2x-3 , x-7/x^2+5x+6

grin007 [14]

Answer:

(x + 3)(x - 1)(x + 2)

Step-by-step explanation:

The fractions are:

$\dfrac{x + 2}{x^{2} + 2x - 3} \text{ and } \dfrac{x - 7}{x^{2} + 5x + 6}$

Factor each denominator

$x^{2} + 2x - 3 = (x + 3)(x - 1)\\x^{2} + 5x + 6 = (x + 3)(x + 2)$

We must find the least common multiple of the denominators. We take the maximum power of each separate factor.

Factors of first fraction = (x + 3) × (x - 1)

Factors of second fraction = (x + 3) × (x + 2)

LCM = (x + 3)(x - 1)(x + 2)

The lowest common denominator of the two fractions is (x + 3)(x - 1) (x + 2).

4 0

3 years ago

In simplified form, V18 is

yulyashka [42]

Answer: 4.24264069

Step-by-step explanation: I think you mean the square root?

4 0

3 years ago

A cell phone company charges $40 per month for unlimited calling, and $0.20 per text message sent. If t represents the number of

kotegsom [21]

Answer: 40 + 0.2t

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

The corners of a meadow are shown on a coordinate grid. Ethan wants to fence the meadow. What length of fencing is required?

Nuetrik [128]

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$A(-6, 2)) = (x_1, y_1)$

$B(2, 6) = (x_2, y_2)$

$AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}$

$AB = \sqrt{(8)^2 + (4)^2}$

$AB = \sqrt{64 + 16} = \sqrt{80}$

$AB = 8.9$ (nearest tenth)

Distance between B(2, 6) and C(7, 1):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$B(2, 6) = (x_1, y_1)$

$C(7, 1) = (x_2, y_2)$

$BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}$

$BC = \sqrt{(5)^2 + (-5)^2}$

$BC = \sqrt{25 + 25} = \sqrt{50}$

$BC = 7.1$ (nearest tenth)

Distance between C(7, 1) and D(3, -5):

$CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$C(7, 1) = (x_1, y_1)$

$D(3, -5) = (x_2, y_2)$

$CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}$

$CD = \sqrt{(-4)^2 + (-6)^2}$

$CD = \sqrt{16 + 36} = \sqrt{52}$

$CD = 7.2$ (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

$DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$D(3, -5) = (x_1, y_1)$

$A(-6, 2) = (x_2, y_2)$

$DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}$

$DA = \sqrt{(-9)^2 + (7)^2}$

$DA = \sqrt{81 + 49} = \sqrt{130}$

$DA = 11.4$ (nearest tenth)

Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units

8 0

3 years ago

Lola gets two 20-minute breaks at work each day. She works 5 days a week. How much time does she spend on break each week?

Maslowich

Answer:

200 minutes / 3 hours & 20 minutes.

Step-by-step explanation:

This is quite simple.

First, since we know that Lola takes two 20 minute breaks at work each day, let's multiply 20 and 2.

20 × 2 = 40

This means she is on break for a total of 40 minutes each day.

Finally, let's take that 40 and multiply it by 5.

40 × 5 = 200

This means she spend 200 minutes (3 hours & 20 mins) on break each week.

8 0

3 years ago

Read 2 more answers