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AfilCa [17]
3 years ago
5

A boxer needs to lose 3 1/2 kg in a month to be able to compete as a flyweight. In three weeks, he lovers his weight from 55.5 k

g to 53.8 kg. How many kilograms must the boxer lose in the final week to be able to compete as a flyweight?
Mathematics
2 answers:
Zielflug [23.3K]3 years ago
6 0

In the final week he need to lose 1.8 kg to be able to compete as a flyweight.

<h3>Further Explanation</h3>

<u>Given:</u>

A boxer needs to lose 3\frac{1}{2} kg

In three weeks he lost 55.5 kg - 53.8 kg

<u>Question:</u>

How many kilograms must the boxer lose in the final week to be able to compete as a flyweight?

He needs to lose 3\frac{1}{2} kg, we can change it into decimal which is 3.5 kg.

Weight he lost in 3 weeks

\boxed {= 55.5 - 53.8 }\\\boxed {= 1.7 kg }\\

In the final week he needs to lose:

\boxed { = 3.5 - 1.7 }\\\boxed {= 1.8 kg }

So, in the final week the boxer needs to lose 1.8 kg

<h3>Learn more</h3>

Math word problem brainly.com/question/997374

Additional that have sum of 10 brainly.com/question/5146571

Mixed fraction brainly.com/question/745462

Keyword: mixed fraction, decimal numbers, subtraction decimal number, convert fraction to decimal

Igoryamba3 years ago
4 0

Answer:

The weight need to lose in final weeks is 1.8 kg

Step-by-step explanation:

we are given

A boxer needs to lose 3 1/2 kg in a month to be able to compete as a flyweight

so, weight need to lose

=3\frac{1}{2}kg

=3.5kg

In three weeks, he lovers his weight from 55.5 kg to 53.8 kg

so, lost weight is

=55.5-53.8kg

=1.7kg

So,

weight need to lose in final weeks = (weight need to lose)-( lost weight)

we can plug values

and we get

weight need to lose in final weeks is

=3.5-1.7

=1.8kg


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3 years ago
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Taya2010 [7]

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Step-by-step explanation:

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7 0
3 years ago
Suppose I ask you to pick any four cards at random from a deck of 52, without replacement, and bet you one dollar that at least
Tatiana [17]

Answer:

a) No, because you have only 33.8% of chances of winning the bet.

b) No, because you have only 44.7% of chances of winning the bet.

Step-by-step explanation:

a) Of the total amount of cards (n=52 cards) there are 12 face cards (3 face cards: Jack, Queen, or King for everyone of the 4 suits: clubs, diamonds, hearts and spades).

The probabiility of losing this bet is the sum of:

- The probability of having a face card in the first turn

- The probability of having a face card in the second turn, having a non-face card in the first turn.

- The probability of having a face card in the third turn, having a non-face card in the previous turns.

- The probability of having a face card in the fourth turn, having a non-face card in the previous turns.

<u><em>1) The probability of having a face card in the first turn</em></u>

In this case, the chances are 12 in 52:

P_1=P(face\, card)=12/52=0.231

<u><em>2) The probability of having a face card in the second turn, having a non-face card in the first turn.</em></u>

In this case, first we have to get a non-face card (there are 40 in the dech of 52), and then, with the rest of the cards (there are 51 left now), getting a face card:

P_2=P(non\,face\,card)*P(face\,card)=(40/52)*(12/51)=0.769*0.235=0.181

<u><em>3) The probability of having a face card in the third turn, having a non-face card in the first and second turn.</em></u>

In this case, first we have to get two consecutive non-face card, and then, with the rest of the cards, getting a face card:

P_3=(40/52)*(39/51)*(12/50)\\\\P_3=0.769*0.765*0.240=0.141

<u><em>4) The probability of having a face card in the fourth turn, having a non-face card in the previous turns.</em></u>

In this case, first we have to get three consecutive non-face card, and then, with the rest of the cards, getting a face card:

P_4=(40/52)*(39/51)*(38/50)*(12/49)\\\\P_4=0.769*0.765*0.76*0.245=0.109

With these four probabilities we can calculate the probability of losing this bet:

P=P_1+P_2+P_3+P_4=0.231+0.181+0.141+0.109=0.662

The probability of losing is 66.2%, which is the same as saying you have (1-0.662)=0.338 or 33.8% of winning chances. Losing is more probable than winning, so you should not take the bet.

b) If the bet involves 3 cards, the only difference with a) is that there is no probability of getting the face card in the fourth turn.

We can calculate the probability of losing as the sum of the first probabilities already calculated:

P=P_1+P_2+P_3=0.231+0.181+0.141=0.553

There is 55.3% of losing (or 44.7% of winning), so it is still not convenient to bet.

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<em><u>Solution:</u></em>

Given that,

<em><u>The volume of cube is given by formula:</u></em>

V = s^3

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"s" is the length of one side

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Given, s = 10 feet

<em><u>Substitute s = 10 in given formula,</u></em>

V = 10^3\\\\V = 10 \times 10 \times 10\\\\V = 1000

Thus volume of cube is 1000 cubic feet

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