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Flura [38]
3 years ago
11

5. Which of the following views is used to run a PowerPoint presentation?

Computers and Technology
2 answers:
goldfiish [28.3K]3 years ago
8 0

Which of the following views is used to run a PowerPoint presentation?

D. slide sorter

Rainbow [258]3 years ago
4 0
D is your answer cause of the powerpoint t
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Paladinen [302]

Answer:

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3 years ago
Which device makes telecommunications possible?
Dmitrij [34]
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7 0
3 years ago
Seven Features of computer aids design software
astra-53 [7]
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3 0
3 years ago
Complete function PrintPopcornTime(), with int parameter bagOunces, and void return type. If bagOunces is less than 2, print "To
Ludmilka [50]

Answer:

#include <iostream>

using namespace std;

void PrintPopcornTime (int bagOunces){

   if (bagOunces < 2){

       cout << "Too small"<<endl;

   }

   else if (bagOunces > 10){

       cout << "Too large"<<endl;

   }

   else{

       cout << bagOunces*6 <<" seconds"<<endl;

   }

}

int main(){

   PrintPopcornTime(7);

   

   return 0;

}

Explanation:

Create a function called PrintPopcornTime that takes one parameter, bagOunces

Check the bagOunces using if-else structure. If it is smaller than 2, print "Too small". If it is greater than 10, print "Too large". Otherwise, calculate and print 6*bagOunces followed by " seconds".

Call the function in the main function with parameter 7. Since 7 is not smaller than 2 or not greater than 10, "42 seconds" will be printed.

4 0
3 years ago
Given a string, convert the characters of the string into opposite case,i.e. if a character is lower case than convert it into u
o-na [289]

Answer:

// CPP program to Convert characters  

// of a string to opposite case  

#include<iostream>  

using namespace std;  

// Function to convert characters  

// of a string to opposite case  

void convertOpposite(string &str)  

{  

int ln = str.length();  

 

// Conversion according to ASCII values  

for (int i=0; i<ln; i++)  

{  

 if (str[i]>='a' && str[i]<='z')  

 //Convert lowercase to uppercase  

  str[i] = str[i] - 32;  

 else if(str[i]>='A' && str[i]<='Z')  

 //Convert uppercase to lowercase  

  str[i] = str[i] + 32;  

}  

}  

// Driver function  

int main()  

{  

string str = "GeEkSfOrGeEkS";  

 

// Calling the Function  

convertOpposite(str);  

 

cout << str;  

return 0;  

}  

Explanation:

8 0
3 years ago
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