3 years ago

Solve the proportion. 8/3 = g/3

1 answer:

5 0

Expression: 8/3 = g/3

Denominators are same, so cancel them from each other.

g = 8

In short, Your Answer would be: 8

Hope this helps!

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The length of a rectangle is 6 cm longer than its width.

oksian1 [2.3K]

2(6+w)+2(w)=40
12+2w+2w=40
12+4w=40
4w=28
w=7
Now we know that the width is 7; abd the length is 7+6 which is 13.
To find the area we multiply 13x7
The area is 92cm squared

4 0

2 years ago

A bag contains yellow marbles and red marbles, 77 in total. The number of yellow marbles is 5 more than 3 times the number of re

bulgar [2K]

Answer:

Step-by-step explanation:

yellow marbles=5+ 3r(r is the number of red marbles)

red marbles=3r

3r+3r+5=77

6r=77-5

6r=72

r=72/6=12

yellow marbles = 5 + 3r

5+ 12 x 3

5+ 36

=41

8 0

2 years ago

5 − c = –11 <br><br> c = ?<br><br> What is C? Please help! I'll give brainliest

jonny [76]

Answer:

Step-by-step explanation:

you would get c alone so you subtract 5 to the other side

4 0

2 years ago

Read 2 more answers

B -2(b - 2) simplified

BlackZzzverrR [31]

Answer:

b -2(b - 2)

b-2b+4

-b+4

4-b

5 0

2 years ago

It is hard to calculate the volume of a mountain but several estimates put the volume of Mount Everest at around 2,413 cubic kil

umka2103 [35]

Answer:

About 609,000 Cowboy stadiums could fit inside of Mount Everest

Step-by-step explanation:

we have

The estimate volume of Mount Everest is at around $2,413\ km^{3}$

The Dallas Cowboys Stadium has a volume of $140,000,000\ ft^{3}$

step 1

Convert ft³ to km³

we know that

1 km=3,280.84 ft

$140,000,000\ ft^{3}=140,000,000*(1/3,280.84)^{3}=0.003964\ km^{3}$

step 2

To find how many Cowboy stadiums could fit inside of Mount Everest, divide the volume of Mount Everest by the volume of the Dallas Cowboys Stadium

$2,413/0.003964=608,729$

Round to the nearest Thousands

$608,729=609,000$

The volume of Mount Everest is about 609,000 times greater than the volume of the Dallas Cowboys Stadium

4 0

2 years ago