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zimovet [89]
3 years ago
13

Help me with this question

Mathematics
2 answers:
r-ruslan [8.4K]3 years ago
6 0

Answer: 3/2a3

I can't properly write the answer sorry but it's the last one.

patriot [66]3 years ago
4 0

Answer:

D choice

Step-by-step explanation:

From:

\displaystyle \large{ \frac{ {9a}^{4} }{ {6a}^{7} } =  \frac{9}{6}  \cdot  \frac{ {a}^{4} }{  {a}^{7} }}

9/6 can be simplified as 3/2.

\displaystyle \large{ \frac{ {9a}^{4} }{ {6a}^{7} } =  \frac{3}{2}  \cdot  \frac{ {a}^{4} }{  {a}^{7} }}

<u>L</u><u>a</u><u>w</u><u> </u><u>o</u><u>f</u><u> </u><u>E</u><u>x</u><u>p</u><u>o</u><u>n</u><u>e</u><u>n</u><u>t</u>

\displaystyle \large{ \frac{ {a}^{m} }{ {a}^{n}  } =  {a}^{m - n} }

Therefore:

\displaystyle \large{ \frac{ {9a}^{4} }{ {6a}^{7} } =  \frac{3}{2}  \cdot  {a}^{4 - 7}  } \\  \displaystyle \large{ \frac{ {9a}^{4} }{ {6a}^{7} } =  \frac{3}{2}  \cdot  {a}^{ - 3}  } \\

<u>L</u><u>a</u><u>w</u><u> </u><u>o</u><u>f</u><u> </u><u>E</u><u>x</u><u>p</u><u>o</u><u>n</u><u>e</u><u>n</u><u>t</u><u> </u><u>I</u><u>I</u>

\displaystyle \large{ {a}^{ - n}  =  \frac{1}{ {a}^{n} } }

Therefore:

\displaystyle \large{ \frac{ {9a}^{4} }{ {6a}^{7} } =  \frac{3}{2}  \cdot   \frac{1}{ {a}^{3} }}

Now, multiply.

\displaystyle \large{ \frac{ {9a}^{4} }{ {6a}^{7} } =  \frac{3}{2 {a}^{3} }  }

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