I'd say around 10%
4 out of 10 = 40%
3 out of the 10 are sold = 30%
1 out of the 3 might be bad = 10%
I may be wrong.
Answer:
24.24%
Step-by-step explanation:
In other words we need to find the probability of getting one blue counter and another non-blue counter in the two picks. Based on the stats provided, there are a total of 12 counters (6 + 4 + 2), out of which only 4 are blue. This means that the probability for the first counter chosen being blue is 4/12
Since we do not replace the counter, we now have a total of 11 counters. Since the second counter cannot be blue, then we have 8 possible choices. This means that the probability of the second counter not being blue is 8/11. Now we need to multiply these two probabilities together to calculate the probability of choosing only one blue counter and one non-blue counter in two picks.
or 0.2424 or 24.24%
Ok slot method
3 slots
1st slot has 52 options
2nd slot has 51 optoins (1 went to first slot)
3rd slot has 50 options (1 went to previous slot)
number of ways=52*51*50=132600 ways
Answer:
Thus every real number other than zero is either positive or negative, while zero itself is not considered to have a sign. Positive numbers are sometimes written with a plus sign in front, e.g. +3 denotes a positive three.