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4 years ago

[50 POINTS]

2 answers:

5 0

A^2 + 2AB + B^2 = (A + B)^2 ==>

16X^2 + 40X + 25 =
= (4X)^2 + 2*4*5X + 5^2 =
= (4X + 5)^2

(4x + 5)(4x + 5)

ExtremeBDS [4]4 years ago

3 0

(4x + 5)(4x + 5) is your final answer.

Hope this helps.

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I'm not sure what you're asking.... but

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3 years ago

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IgorLugansk [536]

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Step-by-step explanation:

Given: $F(x)= \frac{12}{x} + \frac{1}{2}$

To find: Values of the function F(3) , F(−12) , $F(\frac{1}{3})$ , $F(\frac{3}{4})$

Solution:

A function is a relation in which each and every element of the domain has a unique image in the co-domain.

To find the values of the functions $F(3),F(-12),F(\frac{1}{3} ),F(\frac{3}{4} )$ , put $x=3, -12, \frac{1}{3},\frac{3}{4}$ in the given function $F(x)= \frac{12}{x} + \frac{1}{2}$

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