Answer:
<h2><em><u>x</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>32</u></em></h2>
Step-by-step explanation:
4x - 7 - 3x + 4 =25
=> 4x - 3x = 25 + 7
=> <em><u>x = 32 (Ans)</u></em>
Find how much 3% of $5000 is. Then multiply the 3% by five and add it to 5000. I hope that didn’t sound confusing.
P of selecting point on the shaded region = shaded area/whole area
<span>P( selecting point on the shaded ) = ( the four shaded circles ) / the whole square </span>
<span>P of selecting point on the shaded = ( 4 * ( π * r^2 ) )/ x^2 </span>
<span>P of selecting point on the shaded = ( 4 * ( π * (x/4)^2 ) )/ x^2 </span>
<span>P of selecting point on the shaded = ( 4 * ( π * x^2/16 ) )/ x^2 </span>
<span>P of selecting point on the shaded = ( π * x^2/4 )/ x^2 </span>
<span>P of selecting point on the shaded = x^2( π/4 )/ x^2 </span>
<span>P( selecting point on the shaded ) = π/4 ≈ 0.7854 ≈ 79%
=80%
D is right option hope this helps</span>
X - number of the adults, y - number of children;
The system is:
10 x + 6 y = 3292
x + y = 350 => y = 350 - x
----------------------
10 x + 6 * ( 350 - x ) = 3292
10 x + 2100 - 6 x = 3292
4 x = 3292 - 2100
4 x = 1192
x = 1192 : 4
x = 298
y = 350 - 298
y = 52
Answer:
There were 598 adults and 52 children at the showing.
Answer:
It would take 24 minutes for the element to decay to 50 grams
Step-by-step explanation:
The equation for the amount of the element present, after t minutes, is:

In which Q(X) decays radioactively with a half life of 12 minutes.(0) is the initial amount and r is the rate it decreases.
Half life of 12 minutes
This means that 
So








If there are 200 grams of Element X, how long, to the nearest tenth of a minute, would it take the element to decay to 50 grams?
This is t when Q(t) = 50. Q(0) = 200.








It would take 24 minutes for the element to decay to 50 grams