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Komok [63]
4 years ago
9

What is the solution to the linear equation? x – StartFraction 2 Over 3 EndFraction x minus StartFraction one-half EndFraction e

quals StartFraction 1 Over 3 EndFraction plus StartFraction 5 Over 6 EndFraction x. = + x x = –5 x = –negative StartFraction 1 Over 6 EndFraction x = StartFraction 1 Over 6 EndFraction x = 5
Mathematics
2 answers:
Anton [14]4 years ago
5 0

<em>Your question is not well presented</em>

Question:

What is the solution to the linear equation?

x - \frac{2}{3}x - \frac{1}{2} = \frac{1}{3} + \frac{5}{6}x

Answer:

x = \frac{-5}{3}

Step-by-step explanation:

Given

x - \frac{2}{3}x - \frac{1}{2} = \frac{1}{3} + \frac{5}{6}x

Required

Simplify

x - \frac{2}{3}x - \frac{1}{2} = \frac{1}{3} + \frac{5}{6}x

Add \frac{1}{2} to both sides

x - \frac{2}{3}x - \frac{1}{2} + \frac{1}{2} = \frac{1}{3} + \frac{5}{6}x + \frac{1}{2}

x - \frac{2}{3}x = \frac{1}{3} + \frac{5}{6}x + \frac{1}{2}

Subtract \frac{5}{6}x from both sides

x - \frac{2}{3}x - \frac{5}{6}x= \frac{1}{3} + \frac{5}{6}x + \frac{1}{2} - \frac{5}{6}x

x - \frac{2}{3}x - \frac{5}{6}x= \frac{1}{3} + \frac{1}{2} + \frac{5}{6}x- \frac{5}{6}x

x - \frac{2}{3}x - \frac{5}{6}x= \frac{1}{3} + \frac{1}{2}

Take LCMs

\frac{6x - 4x -5x}{6}= \frac{2+3}{6}

\frac{-3x}{6}= \frac{5}{6}

Multiply both sides by 6

6 * \frac{-3x}{6}= \frac{5}{6} * 6

-3x= 5

Divide both sides by -3

\frac{-3x}{-3}= \frac{5}{-3}

x = \frac{5}{-3}

x = \frac{-5}{3}

SCORPION-xisa [38]4 years ago
5 0

Answer:

x=-5

Step-by-step explanation:

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