Question

What is the solution to the linear equation? x – StartFraction 2 Over 3 EndFraction x minus StartFraction one-half EndFraction equals StartFraction 1 Over 3 EndFraction plus StartFraction 5 Over 6 EndFraction x. = + x x = –5 x = –negative StartFraction 1 Over 6 EndFraction x = StartFraction 1 Over 6 EndFraction x = 5

Answer 1

Your question is not well presented

Question:

What is the solution to the linear equation?

$x - \frac{2}{3}x - \frac{1}{2} = \frac{1}{3} + \frac{5}{6}x$

Answer:

$x = \frac{-5}{3}$

Step-by-step explanation:

Given

$x - \frac{2}{3}x - \frac{1}{2} = \frac{1}{3} + \frac{5}{6}x$

Required

Simplify

$x - \frac{2}{3}x - \frac{1}{2} = \frac{1}{3} + \frac{5}{6}x$

Add $\frac{1}{2}$ to both sides

$x - \frac{2}{3}x - \frac{1}{2} + \frac{1}{2} = \frac{1}{3} + \frac{5}{6}x + \frac{1}{2}$

$x - \frac{2}{3}x = \frac{1}{3} + \frac{5}{6}x + \frac{1}{2}$

Subtract $\frac{5}{6}x$ from both sides

$x - \frac{2}{3}x - \frac{5}{6}x= \frac{1}{3} + \frac{5}{6}x + \frac{1}{2} - \frac{5}{6}x$

$x - \frac{2}{3}x - \frac{5}{6}x= \frac{1}{3} + \frac{1}{2} + \frac{5}{6}x- \frac{5}{6}x$

$x - \frac{2}{3}x - \frac{5}{6}x= \frac{1}{3} + \frac{1}{2}$

Take LCMs

$\frac{6x - 4x -5x}{6}= \frac{2+3}{6}$

$\frac{-3x}{6}= \frac{5}{6}$

Multiply both sides by 6

$6 * \frac{-3x}{6}= \frac{5}{6} * 6$

$-3x= 5$

Divide both sides by -3

$\frac{-3x}{-3}= \frac{5}{-3}$

$x = \frac{5}{-3}$

$x = \frac{-5}{3}$

Answer 2

Answer:

x=-5

Step-by-step explanation: