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Naddik [55]
3 years ago
11

What is the area of the rectangular part of the following composite figure?

Mathematics
1 answer:
Vinil7 [7]3 years ago
7 0
It's 48ft².

12 · 4 = 48
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Explain how you know that 3/6 is greater than 1/3 but less than 2/3?
mina [271]
1/3=2/6
2/3=4/6
3/6 is between 2/6 and 4/6
5 0
3 years ago
What is the solution to this equation?<br><br> 0.25 (16x + 12) + 2x = 33
WITCHER [35]
.25(16x + 12) + 2x = 33
The first step is to distribute the .25 to what's inside the parentheses! 
((16x*.25) +(12*.25)) + 2x = 33
Simplify...
4x + 3 +2x = 33
Add like terms...
6x + 3 = 33
Subtract three from both sides
6x + 3 - 3 = 33 - 3
Simplify
6x = 30
Divide each side by six
6x/6 = 30/6
Simplify
x = 5
That's your answer; x = 5! Hope this helped :)
5 0
3 years ago
Read 2 more answers
The function H(t) = −16t2 + 60t + 95 shows the height H(t), in feet, of a projectile after t seconds. A second object moves in t
EleoNora [17]
H(t) = -16t² + 60t + 95
g(t) = 20 + 38.7t

h(1) = -16(1²) + 60(1) + 95 = -16 + 60 + 95 = -16 + 155 = 139
h(2) = -16(2²) + 60(2) + 95 = -16(4) + 120 + 95 = -64 + 215 = 151
h(3) = -16(3²) + 60(3) + 95 = -16(9) + 180 + 95 = -144 + 275 = 131
h(4) = -16(4²) + 60(4) + 95 = -16(16) + 240 + 95 = -256 + 335 = 79

g(1) = 20 + 38.7(1) = 20 + 38.7 = 58.7
g(2) = 20 + 38.7(2) = 20 + 77.4 = 97.4
g(3) = 20 + 38.7(3) = 20 + 116.1 = 136.1
g(4) = 20 + 38.7(4) = 20 + 154.8 = 174.8

Between 2 and 3 seconds. 
The range of the 1st object is 151 to 131.
The range of the 2nd object is 97.4 to 136.1

h(t) = g(t) ⇒ 131 = 131

<span>It means that the point where the 2 objects are equal is the point where the 1st object is falling down while the 2nd object is still going up. </span>
5 0
4 years ago
10 points i guess
Elena-2011 [213]
Part A.
Using the Pythagorean theorem,
  PR² = PQ² +QR²
  PR² = (14 ft)² +(6 ft)² = 196 ft² +36 ft² . . . . substitute the given numbers
  PR² = 232 ft² . . . . . . . . . . . . . . . . . . . . . . . .find the sum
  PR = √(232 ft²) ≈ 15.23 ft . . . . . . . . . . . . . take the square root
The length of rod PR is 15.23 ft.

Part B.
Using the Pythagorean theorem,
  PR² = PQ² +QR²
  (16 ft)² = (14 ft)² +QR² . . . . . . . substitute the given numbers
  256 ft² -196 ft² = QR² . . . . . .. subtract 14²
  60 ft² = QR² . . . . . . . . . . . . . . find the sum
  √(60 ft²) = QR ≈ 7.75 ft . . . . . take the square root
The new height QR is about 7.75 ft.
8 0
4 years ago
Please help, very hard question (for me), Will give Brainliest!!!
AleksAgata [21]
The answer is D. This is because when you take 10.65 and subtract 9.95 from it you get 0.07. If you take this number and continuously add to 9.95 you get the numbers provided in the chart. We'll also notice that the 0.07 is only added after 10 minutes of talking (10,20,30,etc.).
8 0
4 years ago
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