![\bf \begin{array}{llll} &[(-6,2),(2,3),(1,1),(-7,2),(4,2)]\\\\ inverse& [(2,-6),(3,2),(1,1),(2,-7),(2,4)] \end{array} \\\\\\ \textit{is the original a one-to-one?}\qquad \stackrel{rep eated~y-values}{(-6,\stackrel{\downarrow }{2}),(2,3),(1,1),(-7,\stackrel{\downarrow }{2}),(4,\stackrel{\downarrow }{2})}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Bllll%7D%0A%26%5B%28-6%2C2%29%2C%282%2C3%29%2C%281%2C1%29%2C%28-7%2C2%29%2C%284%2C2%29%5D%5C%5C%5C%5C%0Ainverse%26%20%5B%282%2C-6%29%2C%283%2C2%29%2C%281%2C1%29%2C%282%2C-7%29%2C%282%2C4%29%5D%0A%5Cend%7Barray%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Ctextit%7Bis%20the%20original%20a%20one-to-one%3F%7D%5Cqquad%20%5Cstackrel%7Brep%20eated~y-values%7D%7B%28-6%2C%5Cstackrel%7B%5Cdownarrow%20%7D%7B2%7D%29%2C%282%2C3%29%2C%281%2C1%29%2C%28-7%2C%5Cstackrel%7B%5Cdownarrow%20%7D%7B2%7D%29%2C%284%2C%5Cstackrel%7B%5Cdownarrow%20%7D%7B2%7D%29%7D)
notice, the inverse set is just, the same set with the x,y turned to y,x, backwards.
is it a one-to-one? well, for a set to be a one-to-one, it must not have any x-repeats, that is, the value of the first in the pairs must not repeat, and it also must not have any y-repeats, namely the value of the second in the pairs must not repeat.
Answer:
Here is the answer
Step-by-step explanation:
-0.552469136
Btw brainliest me plssssssss
Two times 6 on a dice and one times 2 on the coin
So 6*6*2 = 72
The answer is c. 72
90 is 36% of what number? 250.
Answer:
11x
Step-by-step explanation:
Through addition you can combine like-terms meaning all terms with the same variable. Because of this all of these terms can be combined without too much hassle! :)
