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3 years ago

How do I abbreviate 78 degrees Celsius

Mathematics

1 answer:

lorasvet [3.4K]3 years ago

5 0

Well as far as abbreviation I would put 78°C

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In the diagram below, TUVW is a rectangle. Prove triangle TZW is congruent to triangle UZV.

otez555 [7]

Answer:

By S.S.S. congruence property; ΔTZW ≅ ΔVZU

Step-by-step explanation:

Given:

TUVW is a rectangle.

To Prove : TZW ≅ UZV

Proof:

Since TUVW is a rectangle, and we know that opposite side of a rectangle is equal.

So,

$TW = UV \ \ .\ .\ .\ .\ 1$

And also TV and WU are the diagonals of the rectangle.

And the diagonals of rectangle bisects each other.

Therefore;

$TZ=ZV.........\ 2\\\\WZ=ZU..........\ 3$

Now In ΔTZW and ΔVZU

TW = UV (from 1)

TZ = ZV (from 2)

WZ = ZU (from 3)

So, by S.S.S. congruence property;

ΔTZW ≅ ΔVZU

Hence proved.

8 0

3 years ago

What principal will amount to $3000 if invested at 3% interest compounded

MakcuM [25]

Answer: $2227.41

Step-by-step explanation:

A = P(1 + r/n)^nt

4 0

3 years ago

∠1 and ∠2 are supplementary angles. If m∠1 = 77°, then m∠2 =

posledela

Answer:

B. 103°

Step-by-step explanation:

Supplementary angles add up to 180°, so we can find the measure of angle 2 by subtracting 77 from 180

180 - 77

= 103

So, m∠2 is 103°

7 0

2 years ago

Which statement best describes f(x)=-2√x-7+1

olga nikolaevna [1]

it is under mapping and function

f of x is equal to -2 root x-7 plus one

6 0

3 years ago

Farmer Jones, and his wife, Dr. Jones, decide to build a fence in their field, to keep the sheep safe. Since Dr. Jones is a math

alex41 [277]

Answer: $\frac{8}{3}\times \sqrt{\frac{2}{5}}$

Step-by-step explanation:

Given two upward facing parabolas with equations

$y=6x^2 & y=x^2+2$

The two intersect at

$6x^2=x^2+2$

$5x^2=2$

$x^2$ = $\frac{2}{5}$

x= $\pm \sqrt{\frac{2}{5}}$

area enclosed by them is given by

A= $\int_{-\sqrt{\frac{2}{5}}}^{\sqrt{\frac{2}{5}}}\left [ \left ( x^2+2\right )-\left ( 6x^2\right ) \right ]dx$

A= $\int_{\sqrt{-\frac{2}{5}}}^{\sqrt{\frac{2}{5}}}\left ( 2-5x^2\right )dx$

A= $4\left [ \sqrt{\frac{2}{5}} \right ]-\frac{5}{3}\left [ \left ( \frac{2}{5}\right )^\frac{3}{2}-\left ( -\frac{2}{5}\right )^\frac{3}{2} \right ]$

A= $\frac{8}{3}\times \sqrt{\frac{2}{5}}$

7 0

3 years ago