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frozen [14]
3 years ago
14

How do I abbreviate 78 degrees Celsius

Mathematics
1 answer:
lorasvet [3.4K]3 years ago
5 0
Well as far as abbreviation I would put 78°C
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In the diagram below, TUVW is a rectangle. Prove triangle TZW is congruent to triangle UZV.
otez555 [7]

Answer:

By S.S.S. congruence property;  ΔTZW ≅ ΔVZU

Step-by-step explanation:

Given:

TUVW is a rectangle.

To Prove : TZW ≅ UZV

Proof:

Since TUVW is a rectangle, and we know that opposite side of a rectangle is equal.

So,

TW = UV \ \ .\ .\ .\ .\ 1

And also TV and WU are the diagonals of the rectangle.

And the diagonals of rectangle bisects each other.

Therefore;

TZ=ZV.........\ 2\\\\WZ=ZU..........\ 3

Now In ΔTZW and ΔVZU

TW = UV (from 1)

TZ = ZV (from 2)

WZ = ZU (from 3)

So, by S.S.S. congruence property;

ΔTZW ≅ ΔVZU

Hence proved.

8 0
3 years ago
What principal will amount to $3000 if invested at 3% interest compounded
MakcuM [25]

Answer: $2227.41

Step-by-step explanation:

A = P(1 + r/n)^nt

4 0
3 years ago
∠1 and ∠2 are supplementary angles. If m∠1 = 77°, then m∠2 =
posledela

Answer:

B. 103°

Step-by-step explanation:

Supplementary angles add up to 180°, so we can find the measure of angle 2 by subtracting 77 from 180

180 - 77

= 103

So, m∠2 is 103°

7 0
2 years ago
Which statement best describes f(x)=-2√x-7+1
olga nikolaevna [1]

it is under mapping and function

f of x is equal to -2 root x-7 plus one

6 0
3 years ago
Farmer Jones, and his wife, Dr. Jones, decide to build a fence in their field, to keep the sheep safe. Since Dr. Jones is a math
alex41 [277]

Answer:\frac{8}{3}\times \sqrt{\frac{2}{5}}

Step-by-step explanation:

Given two upward facing parabolas  with equations

y=6x^2 & y=x^2+2

The two intersect at

6x^2=x^2+2

5x^2=2

x^2=\frac{2}{5}

x=\pm \sqrt{\frac{2}{5}}

area  enclosed by them is given by

A=\int_{-\sqrt{\frac{2}{5}}}^{\sqrt{\frac{2}{5}}}\left [ \left ( x^2+2\right )-\left ( 6x^2\right ) \right ]dx

A=\int_{\sqrt{-\frac{2}{5}}}^{\sqrt{\frac{2}{5}}}\left ( 2-5x^2\right )dx

A=4\left [ \sqrt{\frac{2}{5}} \right ]-\frac{5}{3}\left [ \left ( \frac{2}{5}\right )^\frac{3}{2}-\left ( -\frac{2}{5}\right )^\frac{3}{2} \right ]

A=\frac{8}{3}\times \sqrt{\frac{2}{5}}

7 0
3 years ago
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