The following data points represents how many tunnels Gary the groundhog dug each year. 18,5,13,9,6,2,10 using the data to creat
e a histogram
1 answer:
Answer:
The histogram for the data is attached below.
Step-by-step explanation:
The methods commonly used for depicting a frequency distribution are:
- Histogram/Column graph
- Bar graph
- Frequency Polygon
- Pie chart
Out of these, one of the most general and extensively used devices of illustrating a frequency distribution is the histogram.
The data provided for the number of tunnels Gary the groundhog dug each year is:
S = {18, 5, 13, 9, 6, 2, 10}
The histogram for the data is attached below.
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Answer:
A customer who sends 78 messages per day would be at 99.38th percentile.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Average of 48 texts per day with a standard deviation of 12.
This means that
a. A customer who sends 78 messages per day would correspond to what percentile?
The percentile is the p-value of Z when X = 78. So
has a p-value of 0.9938.
0.9938*100% = 99.38%.
A customer who sends 78 messages per day would be at 99.38th percentile.