Answer:
Should be a collective noun.
For example: In addition to those...
Answer:
<u>AP = 13</u>
Step-by-step explanation:
See the attached figure.
CD = 10 and XY = 24
Line XY bisects and is perpendicular to AB and CD
∴ XY bisects at Y
∴ CY = 0.5 CD = 0.5 * 10 = 5
And from the geometry of the shape
P is the midpoint of XY
∴ XP = YP = 0.5 XY = 0.5 * 24 = 12
XY is perpendicular to CD
∴ ΔPYC is a right triangle at Y
∴ PC (hypotenuse) = 
From the figure AP = PC = 13
Answer:
There are a total of possible 1820 results.
Step-by-step explanation:
Since there are two competitions, one for boys and one for girls, and we want all the possible results we will calculate the possible combinations for the boys and multiply them by the possible combinations for the girls. This is shown below:


Total number of possible results:
