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svlad2 [7]
4 years ago
12

M<1=4x m<2=2x-6 find m<8=?

Mathematics
1 answer:
Olegator [25]4 years ago
8 0
I think x will be 144
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Read 2 more answers
Find the dimensions of a rectangle with perimeter 100m area of 336
dalvyx [7]
Start by writing out the formulas for perimeter and area:
P=2L+2W                                                                A=L*W

We know that A = L*W = 336 sq meters and that P=2L + 2W = 100m.

Let's solve the first equation for L:  L = 336/W

Subst. this into the formula for perimeter:  2[336/W] + 2W = 100 m (given)

Now all you have to do is to solve this for W:

336/W + W = 50            becomes 336 + W^2 = 50W.

Then W^2 - 50W + 336 = 0.  Using the quadratic formula, I found that 
          50 plus or minus sqrt (1156)         50 plus or minus 34
W = ----------------------------------------  =  -------------------------------
                                2                                              2

W has to be positive.  Thus, choose W = (50+34) / 2 = 42

Then L = 336 / W, or 336 / 42, or 8.

The dimensions of this rectangle are 8 by 42.

You should check these results.  Does P = 2(8) + 2(42) = 100 ?


8 0
3 years ago
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