5/4 x 22/45
110/ 180
11/18
Answer:
101 meters
Step-by-step explanation:
The direct path across the stream and perpendicular to both sides of the stream is one leg of a right triangle. The 20 meter distance on the arriving side of the stream is another leg of the right triangle. The path he actually took is the hypotenuse of the right triangle.
leg 1 = 99 m
leg 2 = 20 m
hypotenuse = ?
We have a right triangle, and we know the lengths of the two legs. We need to find the length of the hypotenuse, so we can use the Pythagorean theorem.
a^2 + b^2 = c^2
99^2 + 20^2 = c^2
9801 + 400 = c^2
c^2 = 10201
c = sqrt(10201) = 101
Answer: 101 meters
Answer:
Rounding it to two decimal places, we get distance, 
Step-by-step explanation:
Given:
The two points are 
The distance between the two points can be obtained using the distance formula which is given as:
Here, for the points,
Therefore, the distance between the points is:
Rounding it to two decimal places, we get
Answer:
3x + 12
Step-by-step explanation:
Distribute the 3
1. Given any triangle ABC with sides BC=a, AC=b and AB=c, the following are true :
i) the larger the angle, the larger the side in front of it, and the other way around as well. (Sine Law) Let a=20 in, then the largest angle is angle A.
ii) Given the measures of the sides of a triangle. Then the cosines of any of the angles can be found by the following formula:
a^{2}=b ^{2}+c ^{2}-2bc(cosA)
2.
20^{2}=9 ^{2}+13 ^{2}-2*9*13(cosA) 400=81+169-234(cosA) 150=-234(cosA) cosA=150/-234= -0.641
3. m(A) = Arccos(-0.641)≈130°,
4. Remark: We calculate Arccos with a scientific calculator or computer software unless it is one of the well known values, ex Arccos(0.5)=60°, Arccos(-0.5)=120° etc
