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Arte-miy333 [17]
3 years ago
14

How to find the domain of a function

Mathematics
1 answer:
jonny [76]3 years ago
6 0

The space is the arrangement of all conceivable x-values which will influence the capacity "to work", and will yield genuine y-values. When finding the space, recall: The denominator (base) of a part can't be zero. The number under a square root sign must be certain in this segment.

Hope you understand!!!!!!

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Find the equation of the line that passes through (9,-4) and (-1,-8).
Xelga [282]

Answer:

y =  \frac{2}{5} x - 7 \frac{3}{5}

Step-by-step explanation:

<u>Slope-intercept </u><u>form</u>

y= mx +c, where m is the gradient and c is the y-intercept.

\boxed{gradient =  \frac{y1 - y2}{x1 - x2} }

Gradient

=  \frac{ - 4 - ( - 8)}{9 - ( - 1)}

=  \frac{ - 4 + 8}{9 + 1}

=  \frac{4}{10}

=  \frac{2}{5}

Substitute the value of the gradient into the equation:

y =  \frac{2}{5} x + c

To find the value of the y-intercept, substitute a pair of coordinates.

When x= -1, y= -8,

- 8 =  \frac{2}{5} ( - 1) + c

- 8 =  -  \frac{2}{5}  + c

c =  - 8 +  \frac{2}{5}

c =  - 7 \frac{3}{5}

Thus the equation of the line is y =   \frac{2}{5} x - 7 \frac{3}{5}.

7 0
3 years ago
What is the negative reciprocal of 3/4 or three over 4
marishachu [46]
I believe it would be -4/3.
6 0
3 years ago
The function f(x) varies inversely with x and f(x) 0.2 when x= 0.4.
zhannawk [14.2K]
I hope this helps you

7 0
3 years ago
Read 2 more answers
If a⊕ b=a^3−b, and c=101010101010101010 is an 18-digit number, what is c⊕ (c ⊕ c)?
astra-53 [7]

Answer:

<h2>101010101010101010 </h2>

Step-by-step explanation:

given the binary operation a⊕ b=a^3−b and c = 101010101010101010

To get the value of c⊕ (c ⊕ c), we will express the binary given as that in question as shown;

c⊕ (c ⊕ c) = c³-(c ⊕ c)

c⊕ (c ⊕ c) = c³-(c³-c)

On expansion;

c⊕ (c ⊕ c) = c³-c³+c

c⊕ (c ⊕ c) = c

since c =  101010101010101010

c⊕ (c ⊕ c) = 101010101010101010

3 0
3 years ago
Read 2 more answers
X^2+14x-15=0 solve by completing square<br>​
Softa [21]

Answer:

{x}^{2}  + 14x - 15 = 0 \\  {x}^{2}  - x + 15x -15 = 0 \\ x(x - 1) + 15(x - 1) = 0 \\ (x - 1)(x + 15) = 0 \\  \boxed{x = 1} \\  \boxed{x =  - 15}

<h3><u>x=1 and x=</u><u>-</u><u>15</u> is the right answer.</h3>
7 0
3 years ago
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