Step-by-step Explanation:
Part A: Algebraically write the equation of the best fit line in slope-intercept form. Include all of your calculations in your final answer.
Considering the data
Age (in years) Weight (in pounds)
2 32
6 47
7 51
4 40
5 43
3 38
8 60
1 23
Considering the slope intercept form

where
is the slope of the line and
is the y-intercept.
Taking two points, lets say (2, 32) and (8, 60)
as




so





Thus

as
and
substituting in the slop-intercept form

Therefore,
is the equation of the best fit line in slope-intercept form.
Part B: Use the equation for the line of best fit to approximate the weight of the little girl at an age of 14 years old.
As the equation of line is

So in order to find the weight of the little girl at an age of 14 years old, put
in the above equation.
as

∵ 

Therefore, the approximate weight of the little girl at an age of 14 years old will be 88 pounds.