you can round 15 to 20 and 8 and to 10
For this case we have the following equation:
12x2-5x-2 = 0
Using the resolver we have:
x = (- b +/- root (b ^ 2 - 4 * a * c)) / (2 * a)
Substituting values we have:
x = (- (- 5) +/- root ((- 5) ^ 2 - 4 * 12 * (- 2))) / (2 * 12)
Rewriting:
x = (5 +/- root (25 +96))) / (2 * 12)
x = (5 +/- root (121))) / (2 * 12)
x = (5 +/- 11) / (2 * 12)
Answer:
One root is positive and another is negative.
{(0, 4), (2, 4), (3, 7), (4, 9)} is a function.
