All categories

2 years ago

What’s the answer to this question?

Mathematics

1 answer:

Lostsunrise [7]2 years ago

8 0

Answer:

Step-by-step explanation:

You might be interested in

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Match the estimated value of each express

DIA [1.3K]

Answer:

DEAC

Step-by-step explanation:

8 0

1 year ago

Exactly 1 1/3 yard of ribbon is needed to make a bow. Which of the following lengths of ribbon could be used to make a bow with

svp [43]

Answer:

1 and 2/5 yards wastes only 1/15 a yard

Step-by-step explanation:

1 and 1/6 yards would make a waste of 1 and 1/6 yards since you can't make a ribbon out of it. (incorrect)

1 and 2/10 yards would make a waste of 1 and 1/5 yards since you can't make a ribbon out of it. (incorrect)

1 and 2/5 yards

$1\frac{2}{5} -1\frac{1}{3} =\\\\1\frac{6}{15} -1\frac{5}{15} =\\\\\frac{1}{15}$

Wastes 1/15 a yard.

1 and 1/2 yards

$1\frac{1}{2} -1\frac{1}{3} =\\\\1\frac{3}{6} -1\frac{2}{6} =\\\\\frac{1}{6}$

It wastes 1/6 a yard.

2 yards

$2-1\frac{1}{3} =\frac{2}{3}$

It wastes 4/6 a yard.

4 0

2 years ago

Now let’s practice what you have learned.<br><br><br> Solve the equation.<br> 4y – 4 = 28

laiz [17]

Answer:

Step-by-step explanation:

4y-4=28

4y=28+4

4y=32

y=32/4

y=8

now plug in 8 for y and check the equation true:

4y-4=28

4*(8)-4=28

32-4=28

28=28

So, y is equal to eight 8

4 0

2 years ago

Read 2 more answers

Which expression uses the associative property to make it easier to evalute?

mixas84 [53]

Answer:

The correct option is (c).

Step-by-step explanation:

The given expression is :

$14(\dfrac{3}{2}\times \dfrac{1}{4})$

We need to use the associative property to make it easier.

The associative property for multiplication is as follows :

$A\times (B\times C)=(A\times B)\times C$

We have,

$A=14, B=\dfrac{3}{2}\ and\ C=\dfrac{1}{4}$

$14(\dfrac{3}{2}\times \dfrac{1}{4})=(14\times \dfrac{3}{2})\times \dfrac{1}{4}$

Hence, the correct option is (c).

6 0

2 years ago

"if f(x)=x+1/x then the set of values for which f increases is"

Anettt [7]

The solution for this problem would be:
f'(x) = 1 - 1/x^2 = (x^2 - 1)/x^2
is positive where |x| > 1
hence (-inf, -1) and (1, inf) are the regions in which f' is positive and therefore f is increasing.
Therefore, the answer is (-infinity,-1] U [1,infinity).

4 0

2 years ago