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3 years ago

What is the following product? 3 square root of d times 3 square root of d times 3 square root of d

Mathematics

1 answer:

Tanzania [10]3 years ago

7 0

Answer:27d

Step-by-step explanation:

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Convert $2.40 into cents

fgiga [73]

Answer: 240¢

Step-by-step explanation:

100¢ in a dollar.

$2.40 * 100 = 240

240¢

6 0

2 years ago

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Find the co-ordinates of the point where the line y = 3x - 8 crosses the y-axis.

lana66690 [7]

(0,-8)

Explanation: In y=mx + b, m represents the slope of the line and b represents the y intercept, since b is -8, it will cross the y-axis at (0,-8)

4 0

2 years ago

Factors of 72 that add up to 18

Simora [160]

6 and 12 Because 6+12=18

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3 years ago

Complete parts a through c for the given function.

victus00 [196]

Answer:

a. The critcal points are at

$x=0,-5,3$

b. Then, $x = -5$ is a maximum and $x=3$ is a minimum

c. The absolute minimum is at $x = 3$ and the absolute maximum is at $x = -5.$

Step-by-step explanation:

(a)

Remember that you need to find the points where

$f'(x)=0$

Therefore you have to solve this equation.

$20x^4 + 40x^3 - 300x^2 = 0$

From that equation you can factor out $20x^2$ and you would get

$20x^2 ( x^2 +2x - 15) = 0$

And from that you would have $20x^2 = 0$ , so $x = 0$ .

And you would also have $x^2 +2x-15 = 0$ .

You can factor that equation as $x^2 +2x -15 = (x+5)(x-3) = 0$

Therefore $x=-5 , x=3$ .

So the critcal points are at

$x=0,-5,3$

Remember that a function has a maximum at a critical point if the second derivative at that point is negative. Since

$f''(x) = 80x^3 + 120x^2 -600x\\f''(-5) = 80(-5)^3 + 120(-5)^2 -600(-5) = -4000 < 0\\\\f''(3) = 80(3)^3 + 120(3)^2 -600(3) = 1440 > 0 \\$

Then, $x = -5$ is a maximum and $x=3$ is a minimum

The absolute minimum is at $x = 3$ and the absolute maximum is at $x = -5.$

6 0

3 years ago

Read 2 more answers

Please I swear my math teacher is going to kill me

vodomira [7]

5x−y=4

Solve for y

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y=−4+5x

Rewrite in slope-intercept form.

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y=5x−4

Use the slope-intercept form to find the slope and y-intercept.

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Slope: 5

y-intercept: (0,−4)

Any line can be graphed using two points. Select two x

values, and plug them into the equation to find the corresponding y

values.

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xy0−4450

Graph the line using the slope and the y-intercept, or the points.

Slope: 5

y-intercept: (0,−4)

xy0−4450

8 0

2 years ago