Write in summation notation.

The lengths of the sides of a right triangle can be described by the equation a2 + b2 = c2, where a and b are the lengths of the

Luden [163]

An isosceles triangle contains an 2 identical sides and a hypotenuse. The hypotenuse of an isosceles triangle measures √2 as compared to its sides which is 1. In conclusion, to get the sides of an isosceles triangle when given the length of its hypotenuse, divide the length of its hypotenuse by √2 and you should be able to get the length of its sides.

5 0

3 years ago

Read 2 more answers

Can someone help me with these

Stolb23 [73]

Answer:

Problem 2) : the gradient is "-2", and the y-intercept is "3"

Problem 3)

A is $y=2x+2$

B is $y=x+2$

Step-by-step explanation:

Problem 2)

In the line given by the equation: $y=-2x+3$

the "gradient" (also known as "slope") is the numerical coefficient that multiplies the variable "x". So in this case the gradient is "-2"

the y-intercept is the numerical term "+3" because that is the y-value result of evaluating the expression for x = 0

$y=-2x+3\\y=-2\,(0)+3\\y=3$

Problem 3)

Consider the two lines :

$y=x+2$ and $y=2x+2$

notice that both have the same y-intercept (that is the numerical term "2" at the end of both expressions. That means that both lines cross the y-axis at the point y=2.

Now notice that the gradient of one of them is "1" (for $y=x+2$ ) that is the coefficient that multiplies the variable "x". While for the other line ( $y=2x+2$ ) the gradient is "2" and therefore steeper than the previous one.

Then, the line identified as "A" which is the one with steeper gradient, corresponds to the equation $y=2x+2$ , and the line identified with "B" is the one with smaller gradient $y=x+2$ .

6 0

3 years ago

Which relation is a function?

Alja [10]

Answer:

Bottom right

Step-by-step explanation:

Each domain value can only have 1 range value.

8 0

3 years ago

How many times does 9 go into 12?

tamaranim1 [39]

Answer:

one time.

Step-by-step explanation:

5 0

3 years ago

Christov and Mateus gave out candy to children on Halloween. They each have out candy at a constant rate, and they both gave awa

padilas [110]

Answer: 1) Both gave same number of candies to each child.

2) Christov gave candy to a greater number of children.

Step-by-step explanation:

Since, Christov initially had 300 pieces of candy, and after he was visited by 17 children, he had 249 pieces left.

Let he gave x candy to each student when he visited 17 children.

Then, 17 x + 249 = 300

⇒ 17 x = 51

⇒ x = 3

Since, he distributes candies in a constant speed.

Therefore, his speed of distribution = 3 candies per child

Now,The function that shows the remaining number of candies Mateus has after distributing candies to n children,

C(n)=270 - 3 n

Initially, n = 0

C(0) = 270

⇒ Mateus has initial number of candies = 270

When he gave candies to one child then remaining candies = 270 - 3 × 1 = 267

Thus, the candies, get by a child from Mateus = 270 - 267 = 3

Since, he distributes candies in a constant speed.

⇒ His speed of distribution = 3 candies per child

1) Therefore, Both Christov and Mateus have same speed of distribution.

2) Since, both have same seed.

⇒ The one who has greater number of candies will be distribute more.

⇒ Christov will give more candies.

8 0

3 years ago