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Rom4ik [11]
4 years ago
11

Change 0.56 radians into degrees and minutes.

Mathematics
1 answer:
g100num [7]4 years ago
6 0
To change radians to degrees we *by 57.3.56*57.3=3208.8/60=53.48
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The GCF of an odd number and an even number is always even
Oxana [17]
The answer is No it is not
7 0
3 years ago
Where should the point P be chosen on line segment AB so as to maximize the angle θ? (Assume a = 4 units, b = 5 units, and c = 9
taurus [48]
From the figure, let the distance of point P from point A on line segment AB be x and let the angle opposite side a be M and the angle opposite side c be N.

Using pythagoras theorem,
\tan M= \frac{a}{b-x} \\ \\ M=\tan^{-1}\left(\frac{a}{b-x}\right)
and
\tan N= \frac{c}{x} \\ \\ N=\tan^{-1}\left(\frac{c}{x}\right)

Angle θ is given by
\theta=180-M-N \\  \\ =180-\tan^{-1}\left(\frac{a}{b-x}\right)-\tan^{-1}\left(\frac{c}{x}\right)

Given that a = 4 units, b = 5 units, and c = 9 units, thus
\theta=180-\tan^{-1}\left(\frac{4}{5-x}\right)-\tan^{-1}\left(\frac{9}{x}\right)

To maximixe angle θ, the differentiation of <span>θ with respect to x must be equal to zero.
i.e.
\frac{d\theta}{dx} = -\frac{4}{x^2-10x+41} + \frac{9}{x^2+81} =0 \\  \\ -4(x^2+81)+9(x^2-10x+41)=0 \\  \\ -4x^2-324+9x^2-90x+369=0 \\  \\ 5x^2-90x+45=0 \\  \\ x^2-18x+9=0 \\  \\ x=9\pm6 \sqrt{2}

Given that x is a point on line segment AB, this means that x is a positive number less than 5.

Thus
x=9-6 \sqrt{2}=0.5147

Therefore, The distance from A of point P, so that </span>angle θ is maximum is 0.51 to two decimal places.
6 0
4 years ago
How many seconds in an 8 hour work day
aliina [53]
1 hour=3600 seconds
8 times 3600 =28800
8 0
3 years ago
Read 2 more answers
Please help me out!!!!!
Gnoma [55]
Valid because 3 x 3 is 9 :))
3 0
3 years ago
Ok I’m actually dumb lol help me please.
mezya [45]

Answer:

x =20

Step-by-step explanation:

As a line is 180 degrees

So 7x + 40 would be 180, which would lead us with the equation:

7x+40=180

=7x =140 (minus both sides by 40)

=x =20 (divide both sides by 7)

3 0
3 years ago
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