3 years ago

Write as a product of two polynomials: (x-y)^2-a(y-x)

Mathematics

1 answer:

sattari [20]3 years ago

3 0

Answer:

(x - y)(x - y + a)

Step-by-step explanation:

$(x-y)^2-a(y-x) \\ \\ = (x-y)^2 + a(x - y) \\ \\ = (x - y) \{(x - y) + a \} \\ \\ = (x - y)(x - y + a)$

You might be interested in

Can the absolute value of -4 be a negative number

oksian1 [2.3K]

an negative can't be a absolute value

8 0

4 years ago

How do you write 9.58 as a mixed number

kodGreya [7K]

9 58/100 in mixed number form

8 0

3 years ago

Read 2 more answers

400,00 has a value of 400

AfilCa [17]

It cant really because 400,00 is greater than 400 so it would not work

6 0

4 years ago

Determine the general form of the equation for the circle (x – 1)2 + (y + 2)2 = 3.

12345 [234]

(x-1)(x-1) + (y+2)(y+2) = 3

x2 -1x -1x + 1 + y2 +2y +2y +4=3

x2 +y2 -2x +4y + 2=0

A is the answer

6 0

3 years ago

Find u, v , u , v , and d(u, v) for the given inner product defined on Rn. u = (0, −4), v = (5, 3), u, v = 3u1v1 + u2v2

tigry1 [53]

Answer:

$=-12$

$d(u,v)=2\sqrt{31}$

Step-by-step explanation:

We are given that inner product defined on $R_n$

$=3u_1v_1+u_2v_2$

u=(0,-4),v=(5,3)

We have to find the value of <u,v> and d(u,v)

We have $u_1=0,u_2=-4,v_1=5,v_2=3$

Substitute the value then we get

$=3(0\cdot5)+(-4)(3)=-12$

Now, $d(u,v)=\left \|v-u\right \|$

Using this formula we get

$d(u,v)=\left \| (5,7) \right \|=\sqrt{3(5)^2+(7)^2}=\sqrt{75+49}=\sqrt{124}$

$d(u,v)=2\sqrt{31}$

7 0

3 years ago