Ask question

Ask question

All categories

3 years ago

7

The triangular-shaped bases of a prism are 24 cm in length and have a height of 35 cm. Each side is 37 cm. The height of the pri

sm is 29 cm. What is the surface area of the triangular prism?
A) 2192 cm2
B) 2312 cm2
C) 3220 cm2
D) 3682 cm2

1 answer:

Savatey [412]3 years ago

3 0

Answer:

The surface area of Triangular base Prism = 3682 cm²

Step-by-step explanation:

Given in question as :

For a Triangular base prism ,

The base of prism (b) = 24 cm

The height of prism (l) = 29 cm

Each side length (s) = 37 cm

The height of base triangle ( h ) = 35 cm

Hence , we know that The surface area of Triangular base prism is

= (b×h) + (2×l×s) + (l×b)

= (24×35) + (2×29×37) + (29×24)

= (840) + (2146) + (696)

= 3682 cm²

Hence The surface area of Triangular base Prism is 3682 cm² Answer

You might be interested in

What is the percent of change of 24 songs to 78 songs

Novosadov [1.4K]

Subtract 24 to 78. Divide the answer by 24. Multiply it by 100. So the final answer is 225%.
We have a starting value of 24. In order to reach 78, we need to multiply a number to 24 and add it to 24.
Making the equation 24 + 24P = 78.
Transpose 24 to the other side, you’ll get 24P = 78--24.
24P=54.
Divide both sides by 24, you’ll get P = 2.25
Multiply 2.25 by 100 to get the percentage.
So, you’ll get the final answer 225%

3 0

3 years ago

H = 3 + 31t - 161²<br> Find all values of t for which the ball's height is 17 feet .

jasenka [17]

Answer:

t= 31/175 ≈ 5.64516129

Step-by-step explanation:

Refer Pic For Steps....

Hope it Helps!!!

3 0

2 years ago

Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of

IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable <em>X</em> following a Binomial distribution with parameters <em>n </em>and <em>p</em>.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

np ≥ 10
n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided <em>n</em> as follows:

$n_{a}p_{1}=10\times 0.10=1$

Thus, a Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided <em>n</em> as follows:

$n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6$

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided <em>n</em> as follows:

$n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10$

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

8 0

3 years ago

Given GHI G (4,-3), H (-4,2), and I (2,4), find the perpendicular bisector of HI in standard form.

Olin [163]

Answer:

$3x+y=0$

Step-by-step explanation:

step 1

Find the slope of segment HI

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

we have

H (-4,2), and I (2,4)

substitute the given points

$m=\frac{4-2}{2+4}$

$m=\frac{2}{6}$

simplify

$m=\frac{1}{3}$

step 2

Find the slope of the perpendicular line to segment HI

we know that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

$m_1*m_2=-1$

we have

$m_1=\frac{1}{3}$

so

$m_2=-3$

step 3

Find the midpoint segment HI

we know that

The formula to calculate the midpoint between two points is equal to

$M(\frac{x1+x2}{2},\frac{y1+y2}{2})$

we have

H (-4,2), and I (2,4)

substitute

$M(\frac{-4+2}{2},\frac{2+4}{2})$

$M(-1,3)$

step 4

we know that

The perpendicular bisector of HI is a line perpendicular to HI that passes though the midpoint of HI

Find the equation of the perpendicular bisector of HI in point slope form

$y-y1=m(x-x1)$

we have

$m=-3$

$M(-1,3)$

substitute

$y-3=-3(x+1)$

step 5

Convert to slope intercept form

$y=mx+b$

Isolate the variable y

$y-3=-3x-3$

$y=-3x-3+3$

$y=-3x$

step 6

Convert to standard form

$Ax+By=C$

where

A is a positive integer

B and C are integers

$y=-3x$

Adds 3x both sides

$3x+y=0$

see the attached figure to better understand the problem

3 0

4 years ago

Please help i have eman. I will mark brainlist

iragen [17]

Answer:

C

Step-by-step explanation:

8 0

2 years ago