A) -3√288=-3√(144*2)=-3√144<span>√2=-3*12</span><span>√2=-36</span><span>√2
b) </span>5√320=5<span>√(64*5)=</span>5<span>√64</span><span>√5=5*8</span><span>√5=40</span><span>√5</span>
We know from physics class that the formula for distance of
a linear motion is given as:
d = v t
Where,
d = distance travelled
v = average velocity
t = time it took to reach the destination
Since the distance going to the office and back is just
similar, therefore we can simply equate the two:
v1 t1 = v2 t2
Where 1 signifies going to the office and 2 signifies going
back from the office. Therefore this yields to:
v1 * 5 hours = 65 mph * 4 hours
v1 = 52 mph
<span>Answer: The average
speed going to the office is 52 mph.</span>
Your answer will be (B) simply use military time and subtract them and you'll get your answer best of luck.
The y int is where the line crosses the y axis...it is (0,1)...or just 1
1 minute, the number of minutes students stretch when they do not jog
