if becky earns 10.19 per hour they amount she earns in 1 hr is 10.19t . determine if she works 13 hours

What is the ratio given the 2 points

insens350 [35]

Answer:

thankssssssss

Step-by-step explanation:

6 0

3 years ago

Which of the following could be the lengths of the sides of a 30°-60°-90° triangle?

Inga [223]

According to Pythagoras theorem

a^2+b^2=c^2

similarly ,

3^2+ 4^2= 5^2

9+16=25
25=25

LHS=RHS
so angle of triangle is 30 , 60 and 90

answer is 3,4,5

7 0

4 years ago

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When network cards are communicating, bits can occasionally be corrupted in transmission. Engineers have de- termined that the n

ycow [4]

Answer:

a) 11.40% probability of 5 bits being in error during the transmission of 1 kb

b) 11.60% probability of 8 bits being in error during the transmission of 2 kb

c) 0.01% probability of no error bits in 3kb

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the giveninterval.

Poisson distribution with mean of 3.2 bits/kb (per kilobyte).

This means that $\mu = 3.2kb$ , in which kb is the number of kilobytes.

(a) What is the probability of 5 bits being in error during the transmission of 1 kb?

This is P(X = 5) when $\mu = 3.2$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 5) = \frac{e^{-3.2}*3.2^{5}}{(5)!} = 0.1140$

11.40% probability of 5 bits being in error during the transmission of 1 kb

(b) What is the probability of 8 bits being in error during the transmission of 2 kb?

This is P(X = 8) when $\mu = 2*3.2 = 6.4$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 8) = \frac{e^{-6.4}*6.4^{8}}{(8)!} = 0.1160$

11.60% probability of 8 bits being in error during the transmission of 2 kb

(c) What is the probability of no error bits in 3kb?

This is P(X = 0) when $\mu = 3*3.2 = 9.6$

Then

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-9.6}*9.6^{0}}{(0)!} = 0.0001$

0.01% probability of no error bits in 3kb

7 0

3 years ago

For this item, any answers that are not whole numbers should be entered as a decimal, rounded to the tenths place. Brian's schoo

LenaWriter [7]

Answer:

The probability that the locker code begins with a prime number is 40%.
The probability that the last digit of the locker code is an odd number is 40%

Step-by-step explanation:

Prime numbers are the numbers that only divide with 1 or itself. So in this case it is 5 and 7.

The possible combinations are

1*4*3 (with 5) + 1*4*3(with 7) = 24

Total combinations are 5*4*3=60

(24/60)*100 = 40 %

2. Odd numbers are those which don't divide with 2. So in this case it is 6 and 8.

The possible combinations are

1*4*3 (with 6) + 1*4*3(with 8) = 24

Total combinations are 5*4*3=60

(24/60)*100 = 40 %

3 0

3 years ago

PLEASE HELP I WILL GIVE BRAINLIEST Complete the frequency table: Method of Travel to School Walk/Bike Bus Car Row totals Under a

frozen [14]

Answer:

11%

Step-by-step explanation:

1. Fill out the table with the correct numbers.

2. After you fillout the numbers, you should notice that under the column car and in the first row, there should be the number 18.

3. We know the total number of students under the age of 15 is 165.

4. To find the percent:

18/165 * 100

= 11%

3 0

4 years ago

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