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3 years ago

Find the midpoint of the segment with the endpoints:(4, 12) and (-6, 14)

Mathematics

1 answer:

Gnom [1K]3 years ago

3 0

Answer:

A) (-1, 13)

Step-by-step explanation:

$(( - 6 + 4) \div 2)((14 + 12) \div 2)$

$( - 2 \div 2)(26 \div 2)$

-1, 13

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A shopper seeking a bargain combined a 25% off coupon and brought enough money to cover 25% of the base price. Why did this shop

4vir4ik [10]

Because he could only cover 50% of the price 25 by the coupon and 25 which he had.

5 0

4 years ago

Read 2 more answers

See image for question.

klio [65]

Answer:

See below

Step-by-step explanation:

We get possible sums from 1 + 1 = 2 to 6 + 6 = 12 when we toss two dices together. Total ways 6*6 = 36

Prime numbers:

2, 3, 5, 7, 11 - total 5 outcomes with 15 ways (1+1, 1+2, 1+4, 1+6,2+1, 2+3, 2+5, 3+2, 3+4, 4+1, 4+3, 5+2, 5+6, 6+1, 6+5)

P(prime number) = 15/36

Perfect squares:

4, 9 - total 2 outcomes with 3 ways for 4 (1 +3, 2+2, 3+1) and 4 ways for 9 (3+6, 4+5, 5+4,6+3)
P(perfect square) = (3 + 4)/36 = 7/36

Perfect cube:

8 - one outcome with 5 ways (2+6,3+5,4+4,5+3,6+2)
P(perfect cube) = 5/36

8 0

3 years ago

Please help due soon.

attashe74 [19]

Answer:

If Jenny gives her brother 28 marbles, they will have 59 marbles each.

Step-by-step explanation:

The key to finding this answer is a mean, or average. Find it for the number of marbles:

$\text{Mean}=\frac{87+31}{2}= \frac{118}{2}=59 \text{ marbles}$

So, on average, each one should have 59 marbles.

Finally, to find out how many marbles Jenny should give to her brother, subtract the average (59 marbles) from her count:

$87-59=28 \text{ marbles}$

This means Jenny would give up 28 of her marbles to her brother.

5 0

3 years ago

Coordinates (3, 57/3)?

Natalka [10]

Answer:

it is 22

Step-by-step explanation:

have a good day

4 0

3 years ago

Can someone help me?

Marina86 [1]

Answer:

Step-by-step explanation:

Calculate the distance d using the distance formula

d = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }$

with (x₁, y₁ ) = (0, 0 ) and (x₂, y₂ ) = (x, y )

d = $\sqrt{(x-0)^2+(y-0)^2}$

= $\sqrt{x^2+y^2}$ → B

4 0

3 years ago