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erik [133]
2 years ago
9

To the nearest penny, what is the price of 3.2 pounds of ham that costs $2.99 per pound?​

Mathematics
2 answers:
Nutka1998 [239]2 years ago
7 0

\begin{array}{ccll} Lbs&\$\\ \cline{1-2} 1&2.99\\ 3.2&x \end{array}\implies \cfrac{1}{3.2}=\cfrac{2.99}{x}\implies x = (3.2)(2.99)\implies \stackrel{\textit{rounded up}}{x = 9.57}

vichka [17]2 years ago
3 0
$9.56

Explanation:

3 pounds of ham is going to cost $8.97.
To get the 1/5 pound price, multiply the cost of a pound of ham by 1/5 (0.2 in this case) to get $0.568. The final step is to just add the prices together.
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Given: KL ║ NM , LM = 45, m∠M = 50° KN ⊥ NM , NL ⊥ LM Find: KN and KL
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Answer:

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Step-by-step explanation:

Given:

KL ║ NM ,

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1. Consider triangle NLM. This is a right triangle, because NL ⊥ LM. In this triangle,

LM = 45

m∠M = 50°

So,

\tan \angle M=\dfrac{\text{opposite leg}}{\text{adjacent leg}}=\dfrac{NL}{LM}=\dfrac{NL}{45}\\ \\NL=45\tan 50^{\circ}

Also

m\angle LNM=90^{\circ}-50^{\circ}=40^{\circ} (angles LNM and M are complementary).

2. Consider triangle NKL. This is a right triangle, because KN ⊥ NM . In this triangle,

NL=45\tan 50^{\circ}

m\angle KLN=m\angle LNM=40^{\circ} (alternate interior angles)

m\angle KNL=90^{\circ}-40^{\circ}=50^{\circ} (angles KNL and KLN are complementary).

So,

\sin \angle KNL=\dfrac{\text{opposite leg}}{\text{hypotenuse}}=\dfrac{KL}{LN}=\dfrac{KL}{45\tan 50^{\circ}}\\ \\KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08

and

\cos \angle KNL=\dfrac{\text{adjacent leg}}{\text{hypotenuse}}=\dfrac{KN}{LN}=\dfrac{KN}{45\tan 50^{\circ}}\\ \\KN=45\tan 50^{\circ}\cos 50^{\circ}=45\sin 50^{\circ}\approx 34.47

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3 years ago
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Answer:

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