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lawyer [7]
4 years ago
13

-3r + 162-r – 4rsolve rshow work​

Mathematics
1 answer:
Alborosie4 years ago
8 0
-8r+162. If it was equal to zero we could move forward but that’s as simplified it will be.
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A=5<br> b=12<br> c=10<br> d=2<br><br> 2a to the power of 2-c
levacccp [35]

2a is 2 x a

Substitute a =5

2 x 5 =10

Now we have:

10^2-c

Substitute c = 10

(2 - 10 = - 8)

So,it's now 10^ - 8 (10 to the power of - 8)

Ans: 10^ - 8 (or 1 x 10^ -8)

Hope this helps!

5 0
1 year ago
Reduce to simplest form.<br> -3/2 - 3/8
svetlana [45]

Answer:

hope this help you a lot

have a great day

7 0
3 years ago
A homogeneous rectangular lamina has constant area density ρ. Find the moment of inertia of the lamina about one corner
frozen [14]

Answer:

I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)

Step-by-step explanation:

By applying the concept of calculus;

the moment of inertia of the lamina about one corner I_{corner} is:

I_{corner} = \int\limits \int\limits_R (x^2+y^2)  \rho d A \\ \\ I_{corner} = \int\limits^a_0\int\limits^b_0 \rho(x^2+y^2) dy dx

where :

(a and b are the length and the breath of the rectangle respectively )

I_{corner} =  \rho \int\limits^a_0 {x^2y}+ \frac{y^3}{3} |^ {^ b}_{_0} \, dx

I_{corner} =  \rho \int\limits^a_0 (bx^2 + \frac{b^3}{3})dx

I_{corner} =  \rho [\frac{bx^3}{3}+ \frac{b^3x}{3}]^ {^ a} _{_0}

I_{corner} =  \rho [\frac{a^3b}{3}+ \frac{ab^3}{3}]

I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)

Thus; the moment of inertia of the lamina about one corner is I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)

7 0
3 years ago
HELP =(Find the measure of ∠DFG. HELLPP NOW
Sindrei [870]

Answer:

58

Step-by-step explanation:

Add up the angles inside the triangle that are given. All triangles = 180 degrees.

So the missing angle inside the triangle is 122 degrees.

The line is 180 degrees as well, so the angle we are looking for, DFG should be 58 degrees because 180-122 = 58

5 0
4 years ago
Read 2 more answers
Why is 6 over 8 greater than 5 over 8 but less than 7 over 8
azamat
Because 6 over 8 is between 7 over 8 and 5 over 8

6 0
3 years ago
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