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lawyer [7]
4 years ago
13

-3r + 162-r – 4rsolve rshow work​

Mathematics
1 answer:
Alborosie4 years ago
8 0
-8r+162. If it was equal to zero we could move forward but that’s as simplified it will be.
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the figure at the right shows the dimensions of the garden in Marissa's back yard. What is the area of the garden?
vodka [1.7K]

The area of the garden is 74 square feet

<h3>How to determine the area of the garden?</h3>

The complete question is added as an attachment

From the attached figure, we have the following shapes and dimensions:

  • Rectangle: 10 by 5 feet
  • Trapezoid: Bases = 10 and 6; Height = 3

The rectangular area is

A1 = 10 * 5

Evaluate

A1 = 50

The area of the trapezoid is

A2 = 0.5 * Sum of parallel bases * height

This gives

A2 = 0.5 * (10 + 6) * 3

Evaluate

A2 = 24

The total area is

Total = A1 + A2

This gives

Total = 50 + 24

Evaluate

Total = 74

Hence, the area of the garden is 74 square feet

Read more about areas at:

brainly.com/question/24487155

#SPJ1

5 0
1 year ago
Which of the following is equivalent to tan2θcos(2θ) for all values of θ for which tan2θcos(2θ) is defined?
Aloiza [94]

Answer:

2sin²θ - tan²θ

Step-by-step explanation:

Given

tan²θcos(2θ)

Required

Simplify

We start by simplifying cos(2θ)

cos(2θ) = cos(θ+θ)

From Cosine formula

cos(A+A) = cosAcosA - sinAsinA

cos(A+A) = cos²A - sin²A

By comparison

cos(2θ) = cos(θ+θ)

cos(2θ) = cos²θ - sin²θ ----- equation 1

Recall that cos²θ + sin²θ = 1

Make sin²θ the subject of formula

sin²θ = 1 - cos²θ

Substitute sin²θ = 1 - cos²θ in equation 1

cos(2θ) = cos²θ - (1 - cos²θ)

cos(2θ) = cos²θ - 1 +cos²θ

cos(2θ) = cos²θ + cos²θ - 1

cos(2θ) = 2cos²θ - 1

Substitute 2cos²θ - 1 for cos(2θ) in the given question

tan²θcos(2θ) becomes

tan²θ(2cos²θ - 1)

Open brackets

2cos²θtan²θ - tan²θ

------------------------

Simplify tan²θ

tan²θ = (tanθ)²

Recall that tanθ =  sinθ/cosθ

So, we have

tan²θ = (sinθ/cosθ)²

tan²θ = sin²θ/cos²θ

------------------------

Substitute sin²θ/cos²θ for tan²θ

2cos²θtan²θ - tan²θ becomes

2cos²θ(sin²θ/cos²θ) - tan²θ

Open bracket (cos²θ will cancel out cos²θ) to give

2(sin²θ) - tan²θ

2sin²θ - tan²θ

Hence, the simplification of tan²θcos(2θ) is 2sin²θ - tan²θ

Option E is correct

7 0
3 years ago
Your job pays you $9.25/hr
BigorU [14]
I believe it would be $107.32 because each week he earns $138.75 then when you take away the income tax, social security, and your Medicare you have 107.32 dollars left.
$138.75 - 22.65% = 107.32 (Also 22.65 is all of the percent added together, sorry if I'm wrong).
5 0
3 years ago
What is the value of k?
velikii [3]
3
that is the answer for "k" im sure:)
6 0
4 years ago
Give the boundaries of the indicated value. 2 pounds The boundaries are pounds​
Mumz [18]

The limit values of the indicated value, 2 pounds, are the boundaries.

The boundaries of 2 pounds are;

  • 1.5 – 2.5 pounds

<h3>Method used to find the boundaries of the indicated value</h3>

The boundaries of an indicated value are the upper and lower bounds of

the value, which are the possible minimum or maximum values the

number may be before being rounded to the current value.

The indicated value = 2 pounds

The lowest possible value, 2 pounds can be before rounding up is 1.5 pounds.

Therefore;

  • 1.5 pounds is the lower bound of 2 pounds.

The highest possible value of 2 pounds is 2.44999... pounds which is approximately 2.5 pounds

Therefore;

  • The upper bound of 2 pounds is 2.5 pounds

Which gives;

The boundaries of 2 pounds are;

  • <u>1.5 – 2.5 pounds</u>

Learn more about upper and lower bounds here:

brainly.com/question/17644296

8 0
2 years ago
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