When atleast one dice shows a 6 the possible outcomes will be:
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)
(1,6), (2,6), (3,6), (4,6), (5,6)
Thus there are 11 total possible outcomes.
Among these outcomes, the sum of numbers greater than or equal to 9 can be obtained from:
(6,3), (6,4), (6,5), (6,6), (3,6), (4,6), (5,6)
This means there are 7 outcomes with sum greater than or equal to 9.
Thus, Probability of rolling a number greater than or equal to 9 with atleast one dice showing a 6 = 9/11
So, option A gives the correct answer
Answer:
3/4
Step-by-step explanation:
To find the slope of a line parallel to this line, we first need to find the slope of this line. Using rise/run, you get that the slope is 6/8 which simplifies to 3/4.
The slope of any two parallel lines always is the same so the slope of a line parallel to the one given would be 3/4.
Answer:
The adjusting entry for office supplies on March 31 is:
Dr Cr
Supplies Expense 250
Office Supplies 250
Step-by-step explanation:
850+450-1,050 = $250
Beginning Supplies $ 850
Add:Purchase during the month $450
Total Supplies Available $ 1,300
Less: Ending Supplies in hand $ 1,050
Supplies Expenses for March $ 250
Answer:
$95.78
Step-by-step explanation:
f(t) = 300t / (2t² + 8)
t = 0 corresponds to the beginning of August. t = 1 corresponds to the end of August. t = 2 corresponds to the end of September. So on and so forth. So the second semester is from t = 5 to t = 10.
$T₂ = ∫₅¹⁰ 300t / (2t² + 8) dt
$T₂ = ∫₅¹⁰ 150t / (t² + 4) dt
$T₂ = 75 ∫₅¹⁰ 2t / (t² + 4) dt
$T₂ = 75 ln(t² + 4) |₅¹⁰
$T₂ = 75 ln(104) − 75 ln(29)
$T₂ ≈ 95.78
