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ycow [4]
3 years ago
5

If x is a positive integer for how many different values of x is 48/X whole number

Mathematics
2 answers:
Liula [17]3 years ago
7 0

Answer: 3

Step-by-step explanation:

Given that 'x' is a positive integer. We are to find the number of different values of 'x', the square root of is a whole number.

First, we have to find those values of 'x' for which the given fraction is a square.

Therefore, for 3 values of 'x', the given fraction is a square. So, for those 3 values of 'x', the square root of the fraction will be a whole number.

Thus, the answer is 3.

Dimas [21]3 years ago
6 0
Factors of 48 : 1,2,3,4,6,8,12,16,24,48....all of these numbers can be subbed in for X to arrive at a whole number....so there are 10 different ways
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UkoKoshka [18]
1 because you replace x with 2 so, (2)squared -5x2 + 7 = 4 - 10 + 7 = 1
7 0
3 years ago
7 divided into $50.40
PolarNik [594]

Answer:

0.138repeating

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
ricardo lost 6 balls while playing golf.he bought 12 golf balls,then he lost 4 on the course to day.now he has 18 balls.how many
adell [148]
16 golf balls. Hope this helps
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2 years ago
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Can you help me with number 6? <br> Confused abit <br> Please
Sunny_sXe [5.5K]

You can see the three diagram attached. Each link is labeled with the probability: you have probability 1/6 that a six is rolled, and 5/6 that it is not rolled.


To answer the questions, find the path that brings you to the desired outcome, and multiply all the labels you meet.


First question:

To get three sixes, you have to choose the left path at each roll. The probability is always 1/6, so the answer is


\frac{1}{6} \times \frac{1}{6} \times \frac{1}{6} = \frac{1}{6^3}


Second question:

To get no sixes, you have to choose the right path at each roll. The probability is always 5/6, so the answer is


\frac{5}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^3}{6^3}


Third question:

To get exactly one six, it can either be the first, second or third roll.


In all cases, you have to choose the left path once and the right path twice: left-right-right mean that you get the six in the first roll, right-left-right means that you get the six in the second roll, right-right-left means that you get the six in the third roll.


In every case, the left turn has probability 1/6, and the right turn has probability 5/6. The probability of each combination is thus


\frac{1}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^2}{6^3}


And since there are three of these combinations, The answer is


3\frac{5^2}{6^3}


Fourth question:

Since the question suggests to use what we already achieved, let's do it: having at least one six is the complementary event of having no sixes at all. If an event has probability p, its complementary has probability 1-p. So, since the probability of no sixes is known, the probability of at least one six is


1 - \frac{5^3}{6^3}

4 0
3 years ago
The third term in an arithmetic sequence is 58 and the fifth term is 90. if the first term is a1, which is an equation for the n
kiruha [24]
The third term in an arithmetic sequence is 58 and the fifth term is 90. if the first term is a1, which is an equation for the nth term of this sequence?
1. an = 8n + 10
2. an = 8n − 14
☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆3. an = 16n + 10
4. an = 16n − 38

3 0
2 years ago
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